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3 years ago

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Mathematics

1 answer:

Westkost [7]3 years ago

3 0

Answer:

I think it's the 3rd one

Step-by-step explanation:

because it makes sense

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Are the functions f(x) = (x^2-1)/(x-1) and g(x)= x+1 equal for all x?

Vinvika [58]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\$

$\bf f(x)=\cfrac{x^2-1}{x-1}\implies f(x)=\cfrac{x^2-1^2}{x-1}\implies f(x)=\cfrac{(\underline{x-1})(x+1)}{\underline{x-1}}
\\\\\\
f(x)=x+1\qquad \qquad \qquad \qquad \qquad g(x)=x+1\\\\
-------------------------------\\\\
\textit{they're, kinda, except that, when x = 1}
\\\\\\
g(x)=(1)+1\implies g(x)=2
\\\\\\
f(x)=\cfrac{(1)^2-1}{(1)-1}\implies f(x)=\cfrac{0}{0}\impliedby und efined$

7 0

3 years ago

Find the volume of the following solid. The solid between the cylinder f(x,y)equals=e Superscript negative xe−x and the region

PilotLPTM [1.2K]

It is hard to comprehend your question. As far as I understand:

f(x,y) = e^(-x)

Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.

That is all I understood. It would be easier to understand with a picture or some kind of visual aid.

Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

$\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy$

Now evaluate,

$\int_{0}^{ln(6)}e^{-x}dx$

which evaluates to, 5/6 if I did the math correct. Correct me if I am wrong.

Now integrate this w.r.t. y:

$\int_{-6}^{6}\frac{5}{6}dy = 10$

So,

$\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy = 10$

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3 years ago

In Exercises 6 and 7, find sin J, sin K, cos J, cos K, tan J and tan K. Write each answer as a fraction and as a decimal rounded

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Mark Brainliest please

The sine of an angle is defined as the ratio of the opposite side to the hypotenuse.

The cosine of an angle is defined as the ratio of the adjacent side to the hypotenuse.

The tangent of an angle is defined as the ratio of the opposite side to the adjacent side.

See the image for Sin J, K & cos j & K & tan J & K

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3 years ago

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How do you solve an equation when yhe variable is being divided by a whole number

valentinak56 [21]

For example, if x/2=7, x would be equal to 7x2=14, bringing the whole number the variable is divided by to the other side of the equation.

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3 years ago

Why there is 1/3 cup of fruit in half a smoothie

jeka57 [31]

Answer: because the other half is used on the base solution

Step-by-step explanation:

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