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8_murik_8 [283]
3 years ago
15

Which one is it??? ​

Mathematics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

<

Step-by-step explanation:

√7 ≈ 2.66

14/5 = 2.8

2.66 < 2.8

√7 < 14/5

Best of Luck!

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If we list all the natural numbers below 20 that are multiples of 7 or 11, we get 7, 11 and 14. The sum of these multiples is 32
velikii [3]
Number of multiples of 7 up to 1337: \left\lfloor\dfrac{1337}7\right\rfloor=191
Number of multiples of 11 up to 1337: \left\lfloor\dfrac{1337}{11}\right\rfloor=121
Number of multiples of 77 up to 1337: \left\lfloor\dfrac{1337}{77}\right\rfloor=17

This means there are 191+121-17=295 distinct multiples of 7 *or* 11 up to 1337.

The sum of these multiples is

\displaystyle\sum_{k=1}^{191}7k+\sum_{k=1}^{121}11k-\sum_{k=1}^{17}77k

which can be computed using the well-known formula,

\displaystyle\sum_{k=1}^nk=\dfrac{n(n+1)}2

So you have

\displaystyle\sum_{k=1}^{191}7k+\sum_{k=1}^{121}11k-\sum_{k=1}^{17}77k=7\dfrac{191\times192}2+11\dfrac{121\times122}2-77\dfrac{17\times18}2=197762
8 0
3 years ago
Geometry unit 1 lesson 1
nirvana33 [79]
What seems to be the issue?
4 0
4 years ago
A store has a total of 15 bicycles and tricycles. There are 37 wheels. How many tricycles does the store have?
Vlad1618 [11]
X+y=15
2x+3y=37

15-x=y
2x+3(15-x)=37
2x+(45-3x)=37
2x-3x+45=37
-1x=-8
x=8

x is the amount of bikes, so there are 8 bikes. 8x2=16.
37-16=21
21/3=7

There are 7 tricycles.
6 0
3 years ago
Read 2 more answers
What type of relationship does this pair of angles have 67 and 23
diamong [38]

67 + 23 = 90

Because this pair of angles adds up to 90, they are complementary angles.

Hope this helps!! :)

8 0
4 years ago
How many 5 digit numbers are there whose digits sum to 39?
xenn [34]
The distribution of the possible digits of the numbers are
1.) 9, 9, 9, 9, 3  [Number of arrangements = 5! / 4! = 120 / 24 = 5]
2.) 9, 9, 9, 8, 4  [Number of arrangements = 5! / 3! = 120 / 6 = 20]
3.) 9, 9, 9, 7, 5  [Number of arrangements = 5! / 3! = 120 / 6 = 20]
4.) 9, 9, 9, 6, 6  [Number of arrangements = 5! / (3! x 2!) = 120 / 12 = 10]
5.) 9, 9, 8, 8, 5  [Number of arrangements = 5! / (2! x 2!) = 120 / 4 = 30]
6.) 9, 9, 8, 7, 6  [Number of arrangements = 5! / 2! = 120 / 2 = 60]
7.) 9, 9, 7, 7, 7  [Number of arrangements = 5! / (3! x 2!) = 120 / 12 = 10]
8.) 9, 8, 8. 8, 6  [Number of arrangements = 5! / 3! = 120 / 6 = 20]
9.) 9, 8, 8, 7, 7  [Number of arrangements = 5! / (2! x 2!) = 120 / 4 = 30]
10.) 8, 8, 8, 8, 7  [Number of arrangements = 5! / 4! = 120 / 24 = 5]

Number of 5 digit numbers whose digit sum up to 39 = 5 + 20 + 20 + 10 + 30 + 60 + 10 + 20 + 30 + 5 = 210
6 0
3 years ago
Read 2 more answers
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