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8_murik_8 [283]
3 years ago
15

Which one is it??? ​

Mathematics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

<

Step-by-step explanation:

√7 ≈ 2.66

14/5 = 2.8

2.66 < 2.8

√7 < 14/5

Best of Luck!

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Two sides of a triangle have measures 3 ft and 6 ft. Also, these sides form a vertex whose angle measures 60 degrees. Calculate
Basile [38]

Answer:

A. The length of the third side is approximately 5 feet.

B. A = 88^{o}, B = 60^{o} and C = 32^{o}.

Step-by-step explanation:

Let the triangle be ABC. Given two sides and an included angle, let us apply the cosine rule to determine the third length.

A. Let side a = 6 feet and c = 3 feet, thus;

b^{2} = a^{2} + c^{2} - 2ac Cos B

  = 6^{2} + 3^{2} - 2(6 x 3) Cos 60^{o}

  = 36 + 9 - 36 x 0.5

  = 45 - 18

b^{2} = 27

b = \sqrt{27}

  = 5.1962

b  = 5.2 feet

b ≅ 5 feet

The length of the third side is approximately 5 feet.

B. Given that B = 60^{o}, then let us apply the Sine rule to determined the measure of A.

\frac{a}{SinA} = \frac{b}{SinB}

So that,

\frac{6}{Sin A} = \frac{5.2}{Sin60^{o} }

Sin A = \frac{0.886*6}{5.2}

Sin A = 0.99923

A = Sin^{-1} 0.99923

  = 87.75

A ≅ 88^{o}

Since the sum of angle in a triangle = 180^{o}.

Then,

A + B + C = 180^{o}

88^{o} + 60^{o} + C = 180^{o}

148^{o} + C = 180^{o}

C = 180^{o} - 148^{o}

     = 32^{o}

C = 32^{o}

Thus,

A = 88^{o}, B = 60^{o} and C = 32^{o}.

5 0
3 years ago
I need help with this proof
Maksim231197 [3]

Answer:

See explanation

Step-by-step explanation:

Consider two triangles ABF and EDF. These triangles are two right triangles, because angles B and D are right anges.

In these triangles,

  • ∠ABF ≅ ∠EDF - as two right angles;
  • BF ≅ FE - given;
  • ∠AFB ≅ ∠EFD - as vertical angles when two lines AD and BE itersect.

By ASA postulate (or HA postulate) these triangles are congruent, so

ΔABF ≅ ΔEDF

Congruent triangles have congruent corresponding parts, so

FA ≅ EF

6 0
3 years ago
Make a number line and show all values of x such that: x less than or equal to -2 or x&lt;-5
Mila [183]
I uploaded the answer here is the link : jim hb/
5 0
3 years ago
Simplify : (√ + √ ) (√ − √) ( + )( 2 + 2 )
jek_recluse [69]

(\sqrt{x}+\sqrt{y})(\sqrt{x}-\sqrt{y})(x+y)(x^2+y^2)\\\\=[(\sqrt{x})^2-(\sqrt{y})^2](x+y)(x^2+y^2)\\\\=(x-y)(x+y)(x^2+y^2)\\\\=(x^2-y^2)(x^2+y^2)\\\\=(x^2)^2-(y^2)^2\\\\=x^4-y^4


Used:\\\\(\sqrt{a})^2=a\\\\(a-b)(a+b)=a^2-b^2\\\\(a^n)^m=a^{nm}

6 0
3 years ago
tim brought a car 25000 and it depreciation $350 per year. What is the value of the car after 6 years?
blondinia [14]

Answer:

22900

Step-by-step explanation:

multiply 350 by 6 and get 2100

subtract 2100 from 25k and get 22900

6 0
4 years ago
Read 2 more answers
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