<span>dividend x3 - 11x2 + 16x + 84
- divisor * x2 x3 - 7x2
remainder - 4x2 + 16x + 84
- divisor * -4x1 - 4x2 + 28x
remainder - 12x + 84
- divisor * -12x0 - 12x + 84
remainder 0
Quotient : x2-4x-12 Remainder: 0
Step-1 : Multiply the coefficient of the first term by the constant 1 • -12 = -12
Step-2 : Find two factors of -12 whose sum equals the coefficient of the middle term, which is -4 .
-12 + 1 = -11
-6 + 2 = -4 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -6 and 2
x2 - 6x + 2x - 12
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-6)
Add up the last 2 terms, pulling out common factors :
2 • (x-6)
Step-5 : Add up the four terms of step 4 :
(x+2) • (x-6)
Which is the desired factorization
Final result :
(x + 2) • (x - 6) • (x - 7)</span>
Answer:
1)Take the smallest power common
2) simply the bracket
3) multiply with the power taken common
Example:
5×10⁶ - 4×10³
Smaller power is 3, so take 10³ common:
10³[(5×10²) - 4]
10³[500 - 4]
10³(496)
496×10³
4.96×10⁵
Answer:
See below for answer.
Step-by-step explanation:
RP/RT =RQ/RS Given
∠R = ∠R
ΔPQR similar to Δ TSR If the measures of two sides of a triangle are proportional to the measures of two corresponding sides of another triangle and their included angles are congruent, then the triangles are similar.
I believe the correct answer is D. (if it’s not D then A)
The required solution is ∠RQT = 202° and ∠QTS = 51°
<h3 />
<h3>What is a cyclic quadrilateral?</h3>
A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also called as inscribed quadrilateral.
Its main property is that the sum of opposite angles of inscribed quadrilateral is always 180 degrees.
Now, the given circle has a cyclic quadrilateral QRST in which it is given that ∠RQT = 202° and ∠QRS = 129°
Since,sum of the opposite angles of a cyclic quadrilateral = 180°
⇒∠QTS + ∠QRS = 180°
⇒ ∠QTS + ∠129° = 180°
⇒ ∠QTS = 180° - ∠129°
⇒ ∠QTS = 51°
Hence,the requires angles are ∠RQT = 202° and ∠QTS = 51°.
More about cyclic quadrilateral :
brainly.com/question/14323008
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