Question

Find the equation of the line that passes through the point (2,2) and is perpendicular to the line

Answer 1

Y = mx + c, where m is your gradient and c is your y intercept.

If the line is perpendicular to the line y = 3x - 5, the line's gradient = -(1/3) as when it comes to perpendicular bisector, m1/m2 = -1

y = -(1/3)x + C
To find C sub in x=2 and y=2 as it goes through (2,2)

2 = -(1/3)2 + C
2 = -(2/3) + C
2 + 2/3 = C
C = 8/3

There your equation of a line is
y = -(1/3)x + 8/3