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andrey2020 [161]
3 years ago
11

Find the equation of the line that passes through the point (2,2) and is perpendicular to the line

Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0
Y = mx + c, where m is your gradient and c is your y intercept.

If the line is perpendicular to the line y = 3x - 5, the line's gradient = -(1/3) as when it comes to perpendicular bisector, m1/m2 = -1

y = -(1/3)x + C
To find C sub in x=2 and y=2 as it goes through (2,2)

2 = -(1/3)2 + C
2 = -(2/3) + C
2 + 2/3 = C
C = 8/3

There your equation of a line is
y = -(1/3)x + 8/3

You might be interested in
Please help me with those question please help with out number 1
alina1380 [7]

Answer:

1) For each value of x, a value of y is increased by 5.

x = 0, y = 5

x = 1, y = 10

x = 2, y = 15

x = 3, y = 20

------------------------------------------------------------------------------------------

2) For each two values of x, a value of y is increased by 10.

x = 0, y = -2

x = 2, y = 8

x = 4, y = 18

x = 6, y = 28

-------------------------------------------------------------------------------------------

3)

x = 0, y = 1

x = 1, y = \frac{7}{5}

x = 5, y = 3

x = 10, y = 5

-------------------------------------------------------------------------------------------------

4)

x = 0, y = 2

x = 1, y = 17

x = 2, y = 32

x = 5, y = 77

Step-by-step explanation:

This is as easy as replacing x for the actual value show on the table.

1)

y=5x+5

When x = 0, y = ?

y=5(0)+5\\y=0+5\\y=5

When x = 1, y = ?

y=5(1)+5\\y=5+5\\y=10

When x = 2, y = ?

y=5(2)+5\\y=10+5\\y=15

When x = 3, y = ?

y=5(3)+5\\y=15+5\\y=20

-------------------------------------------------------------------------------------------------------

2)

y=5x-2

When x = 0, y = ?

y=5(0)-2\\y=0-2\\y=-2

When x = 2, y = ?

y=5(2)-2\\y=10-2\\y=8

When x = 4, y = ?

y=5(4)-2\\y=20-2\\y=18

When x = 6, y = ?

y=5(6)-2\\y=30-2\\y=28

----------------------------------------------------------------------------------------------------

3)

y=\frac{2}{5}x +1

When x = 0, y = ?

y=\frac{2}{5}(0) +1

y=0 +1\\y=1

When x = 1, y = ?

y=\frac{2}{5}(1) +1\\y=\frac{2}{5} +1

y=\frac{2}{5}+1(\frac{5}{5})\\ y=\frac{2}{5}+\frac{5}{5}  \\y=\frac{7}{5}

When x = 5, y = ?

y=\frac{2}{5}(5) +1\\y=2+1\\y=3

When x = 10, y = ?

y=\frac{2}{5}(10) +1\\y=2(2) +1\\y=4+1\\y=5

-------------------------------------------------------------------------------------------------

4)

y=15x+2

When x = 0, y = ?

y=15(0)+2\\y=0+2\\y=2

When x = 1, y = ?

y=15(1)+2\\y=15+2\\y=17

When x = 2, y = ?

y=15(2)+2\\y=30+2\\y=32

When x = 5, y = ?

y=15(5)+2\\y=75+2\\y=77

4 0
3 years ago
Read 2 more answers
Verify the identity. <br><br> cos 4x + cos 2x = 2 - 2 sin^2(2x) - 2 sin^2 x
Advocard [28]
So are you trying to simplify one side to get it to look like the other?
8 0
2 years ago
A rectangular Corn Hole area at the Recreation Center has a width of 5 feet and a length of 10 feet. If
inysia [295]

Answer:

2 feet

Step-by-step explanation:

Let

x ----> the uniform amount added to each side

we know that

The algebraic expression that represent this situation is

(5+x)(10+x)=84

solve for x

Apply distributive property

50+ 5x+10x+x^2=84\\x^2+15x-34=0

solve the quadratic c equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^2+15x-34=0  

so

a=1\\b=15\\c=-34

substitute in the formula

x=\frac{-15\pm\sqrt{15^{2}-4(1)(-34)}} {2(1)}

x=\frac{-15\pm\sqrt{361}} {2}

x=\frac{-15\pm19} {2}

x=\frac{-15\pm19} {2}=2

x=\frac{-15\pm19} {2}=-17

therefore

The solution is x=2 ft

8 0
3 years ago
Solve the proportion.<br><br> s+1/4 = 4/8<br> s=
LUCKY_DIMON [66]

Answer:

8 = 16

Step-by-step explanation:

1/4  =  4 /8

 

Cross multiply:

1 * 8 = 4 * 4

Simplifying

1 * 8 = 4 * 4

Multiply 1 * 8

8 = 4 * 4

Multiply 4 * 4

8 = 16

Solving

8 = 16

3 0
3 years ago
Graph of a cubic polynomial that falls to the left and rises to the right with x intercepts negative 2, negative 1, and 2
xz_007 [3.2K]
Hello,

A cubic polynomial with -2,1,2 as roots is
f(x)=k*(x+2)(x+1)*(x-2)=k(x²-4)(x+1)=k(x^3+x²-4x-4)

Looking the answers ==>k=1


==>Answer A
6 0
3 years ago
Read 2 more answers
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