Answer:
ASA
Step-by-step explanation:
You can show the angles at either end of segment BC in triangles MBC and LCB are congruent, so you have two angles and the segment between. The appropriate theorem in such a case is ASA.
point slope form:y-2=4(x+1)
then distribute 4 and simplify y-2=4x+4 , y=4x+6 is the slope -y intercept form
then, move 4x on the left side, you get -4x+y=6 , multiply every term by -1, you get 4x-y=-6 which is standard form.
So, let's start off with explaining what these different questions mean;
y = |x + c| Shifts the graph c units left.
y = |x - c| Shifts the graph c units right.
y = |x| + c Shifts the graph c units up.
y = |x| - c Shifts the graph c units down.
(0,0) Is the starting point on any graph like this. So, determine the answer by going through the list of answers.
I believe the answer is y = 2x.
I would like to know if I am wrong so contact me!!
Answer:

Step-by-step explanation:
Given:
The function 'g(x)' is given as:

Now, the function 'f(x)' is given as:

So, the function 'f(x)' is a transformation of 'g(x)'.
In order to find f(x), we replace 'x' by
in the 'g(x)' function equation. This gives,

Using the identity
, we get:

Hence the function f(x) is given as:

Answer: its b
Step-by-step explanation: