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3 years ago

Find the median And mode of 8,3,12,5,2,9,3

Mathematics

2 answers:

solmaris [256]3 years ago

8 0

The median is 5 and the mode is 3.

jok3333 [9.3K]3 years ago

6 0

Mode is the score that occurs most often

In this data set, the mode is three because it occurs two times

To find the median, you list th scores form smallest to biggest

2, 3, 3, 5, 8, 9, 12

Cross off the first three score and the last three scores so that you are left with the middle score of five

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A teacher keeps track of how many books are read by students in each class. Which grade has read has read a higher rate hook per

12345 [234]

For the answer to the question above asking how many more book does the other grade need to read to have the same rate?
I think the answer here is the 7 grader needs to read 94 more books in order to catch up with 6 grade.

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3 years ago

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hi i'm really struggling with this and its due later today! If someone could show the work of how to do it and the answer that w

GuDViN [60]

Answer:

$\frac{-5 \pm \sqrt{13} }{6}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

Step 1: Define

$\frac{-5 \pm \sqrt{5^2-4(3)(1)} }{2(3)}$

Step 2: Evaluate

Evaluate Exponents: $\frac{-5 \pm \sqrt{25-4(3)(1)} }{2(3)}$
Evaluate Multiplication: $\frac{-5 \pm \sqrt{25-12} }{6}$
Evaluate Subtraction: $\frac{-5 \pm \sqrt{13} }{6}$

8 0

3 years ago

Drawing Conclusions

maksim [4K]

Answer:

Some of the Exponents = -2 that is true, not 2.

Step-by-step explanation:

Let's check one at a time.

(a)The 6 without an exponent is equivalent to the 6 having a 0 exponent.

$6^{0} =1$ and $6^{1}$ = 6 (no exponent. 6 $\neq$ 1 therefore this statement is False.

(b)The sum of the exponents is -2.

let's check , if the base is same we can add the exponents that is the exponent rule.(well established).

if we add exponents in the given expression we get.

$6^{1} 6^{0} 6^{3} =6^{1+0+(-3)} =6^{-2}$ , therefore we can see that the sum of the exponents = -2 this is true.

(c) An equivalent expression is 65.6-7, lets evaluate our above expression, it is equal to $\frac{1}{36}$ which we can see that $\frac{1}{36} \neq 65.6-7$ ,therefore this statement is false as well.

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3 years ago

Jhalen gave a presentation in health class about the importance of supportive sneakers. His presentation was 2/3 the length of L

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Answer: Lenayah's presentation was 12 minutes long.

Step-by-step explanation:

Set up a proportion. 2/3 = 8/x.
Cross multiply. 2x = 24
Divide both sides by 2. x =12

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3 years ago

The particle of dust has a mass of 7.53x10 to the-10 kilograms. Find the weight of 5 billion dust particles

Vitek1552 [10]

Multiply the dust particle mass by 5 billion..
On a calculator use the "EE" button is shorthand for: x10^ whatever power you want.
5x10^9 x 7.53x106-10 = 3.765

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2 years ago

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