Question

Find the equation of the line specified.

Answer 1

Answer:

y = 6x + 28

Step-by-step explanation:

We are to determine the equation of a line whose slope or gradient is 6 and passes through the point (-4, 4)

The slope-intercept form of the equation of the straight line would be given by;

y = mx + c

y = 6x + c

We proceed to use the given point to determine c;'

when x = -4, y = 4

4 = 6(-4) + c

4 = -24 + c

c = 28

The slope-intercept form of the equation of the straight line is thus;

y = 6x + 28

Answer 2

For this case we have that by definicon, the equation of a line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut point with the y axis.

They tell us that the slope is 6, then:

$y = 6x + b$

We substitute the given point, to find the cut point:

$4 = 6 (-4) + b\\4 = -24 + b\\b = 4 + 24\\b = 28$

Finally:

$y = 6x + 28$

Answer:

Option D