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3 years ago

What type of graph is this?

Mathematics

1 answer:

murzikaleks [220]3 years ago

5 0

Answer:

The graph of a quadratic equation, or a parabola, looks like a U, an upside down U, a C, or a backwards C. We can use the following rules to determine what the graph of a given quadratic equation looks like. If y = ax2 + bx + c, and a is positive, then the graph of the equation is the shape of a U.

Step-by-step explanation:

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133/28=x/4 <br> x=? <br> !!!!!!!!!!!!!!!!!!!!!

den301095 [7]

$\frac{133}{28}= \frac{x}{4} 
 \\ =\ \textgreater \ x= \frac{133*4}{28}=19$

7 0

3 years ago

5x^3+9x^2+6x+1 times the polynomial x?

zhannawk [14.2K]

Answer:

$(5x^{4} + 9x^{3} + 6x^{2} + 1x)$

Step-by-step explanation:

$(5x^{3} + 9x^{2} + 6x + 1) * x$

Multiplying the term by x, adds 1 to the power.

$5x^{3} * x = 5x^{3+1} = 5x^{4}$

Therefore

$(5x^{3} + 9x^{2} + 6x + 1) * =\\(5x^{4} + 9x^{3} + 6x^{2} + 1x)$

6 0

3 years ago

Keith has $500 in a savings account at the beginning of

k0ka [10]

Answer:

500-25w $\geq$ 200

Step-by-step explanation:

3 0

2 years ago

,,,,,,,,,,,,,,,,,,,,,,,,,

jonny [76]

Answer:

side

Step-by-step explanation:

if your talking about the dark purple it would be the side but if your talking about the other one it would be front i cant rlly tell by the colors.

i hope this helps:)

8 0

2 years ago

A community theater uses the function p (d) = (-4d+40) (d−40) to model the profit (in dollars) expected in a weekend when the ti

fomenos

The theater make the maximum profit at d = $25. Then the maximum profit of the theatre is $ 900.

<h3>What is differentiation?</h3>

The rate of change of a function with respect to the variable is called differentiation. It may be increasing or decreasing.

A community theater uses the function P(d) = (− 4d + 40) (d − 40) to model the profit (in dollars) expected on a weekend when the tickets to a comedy show are priced at d dollars each.

Then the maximum profit of the theatre will be

The function is P(d) = (− 4d + 40) (d − 40)

Differentiate the function with respect to d and put it equal to zero for maximum or minimum profit.

$\begin{aligned} \dfrac{\mathrm{d} }{\mathrm{d} d}P(d) &= 0\\\\\dfrac{\mathrm{d} }{\mathrm{d} d}(- 4d + 40) (d - 40) &= 0\\\\(-4d+40) -4 (d-40) &= 0\\\\-8d + 200 &= 0\\\\d &= 25 \end{aligned}$

Then the checking for maximum or minimum, again differentiate, we have

$\begin{aligned} \dfrac{\mathrm{d} }{\mathrm{d} d}P(d) &= \dfrac{\mathrm{d} }{\mathrm{d} d}(- 4d + 40) (d - 40) \\\\\dfrac{\mathrm{d} }{\mathrm{d} d}P(d) &= \dfrac{\mathrm{d} }{\mathrm{d} d}(-8d + 200) \\\\\dfrac{\mathrm{d} }{\mathrm{d} d}P(d) &= -8\\\\ \dfrac{\mathrm{d} }{\mathrm{d} d}P(d) & < 0\end{aligned}$

The value is less than zero hence maximum value will occur at d = 25.

Then maximum profit will be

P(d) = (− 4×25 + 40) (25 − 40)

P(d) = (− 100 + 40) (−15)

P(d) = (− 60) (− 15)

P(d) = $ 900

More about the differentiation link is given below.

brainly.com/question/24062595

#SPJ1

7 0

2 years ago