<span>Cone Volume = (<span>π<span> • r² •<span> h) ÷ 3
radius^2 = (3 * Volume) / (PI * height)
</span></span></span></span><span>radius^2 = (3 * 12) / (PI * 3)
radius^2 = (36)/ (</span><span>9.4247779608) </span><span>
radius^2 = </span>
<span>
<span>
<span>
3.8197186342
</span>
</span>
</span>
radius =
<span>
<span>
<span>
1.95</span></span></span>
Answer:
Altitude of the plane is 0.5 miles.
Step-by-step explanation:
From the figure attached,
An airplane A is at height h miles observes a small airstrip at D and a factory at F, 4.8 miles apart from D.
Angle of depressions for the airstrip is 13.1° and the factory is 4.1°.
We have to calculate the airplane's altitude h.
From ΔABF,
tan4.1 = 
h = 0.07168(x + 4.8) -----(1)
From ΔABD,
tan13.1 = 
h = 0.2327x -----(2)
From equation (1) and (2),
0.07168(x + 4.8) = 0.2327x
0.2327x - 0.07168x = 4.8×0.07168
0.161x = 0.344
x =
miles
From equation (2),
h = 0.2327×2.137
h = 0.4972 miles
h ≈ 0.5 miles
Therefore, 0.5 miles is the altitude of the plane.
Us girls are disgusted <3
step by step explanation: