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n200080 [17]
3 years ago
9

(2/3)-(1/X+6)=2 solve for x

Mathematics
1 answer:
nata0808 [166]3 years ago
8 0
We have a fraction with the unknown in the denominator, review how to treat unknowns in the denominator as a refresher for this exercise:
<span>(2/3) - (1/x + 6) = 2
</span>(2/3) - (1 + 6x)/x = <span>2
</span>(2/3) - 2 = (1 + 6x)/x
2/3 - 6/3 = (1 + <span>6x)/x
-4/3 = </span>(1 + <span>6x)/x
-4x = 3</span>(1 + <span>6x)
</span><span>-4x = 3 + 18x
</span>22x = -3
x = -3/22
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\boxed{\boxed{ \ 0.061 \frac{inch^3}{cm^3}\ }}

<h3>Further explanation</h3>

We will calculate the unit conversion factor used to convert its engine displacement from cubic-centimeters to cubic-inches.

The relationships between inch and cm are as follows:

\boxed{ \ 1 \ inch = 2.54 \ cm\ }

Inches and cm represent units of length.

Made into fractions, 1 inch as the denominator and 2.54 cm as the numerator.

\boxed{ \ \frac{1 \ inch}{2.54 \ cm} \ }

As a unit conversion factor of volume, the numerator and the denominator in cubic.

\boxed{ \ \frac{(1 \ inch)^3}{(2.54 \ cm)^3} \ }

\boxed{ \ \frac{1 \ inch^3}{16.387 \ cm^3} \ }

Thus, we get the unit conversion factor

\boxed{\boxed{ \ 0.061 \frac{inch^3}{cm^3}\ }}

Let's use this unit conversion factor to calculate its engine displacement in new units.

\boxed{= 1,043 \ cm^3 \times 0.061 \ \frac{inch^3}{cm^3}}

Note for cm³ units that have been crossed out.

The conversion result is \ \boxed{ \ 63.623 \ inch^3\ }

<h3>Learn more</h3>
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Keywords: the motorcycle engine, Kawasaki Ninja 1000, 1043 cubic-centimeters (cm³), to calculate, its engine displacement, in cubic-inches (in³), what unit conversion factor

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