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Alecsey [184]
3 years ago
12

URGENT!!

Mathematics
1 answer:
Finger [1]3 years ago
4 0

Answer:

Part a) The inequality that represent the situation is

x+(3x)+(6x) \leq 350\ in  

Part b) The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to 35\ inches

Step-by-step explanation:

Let

x------> the length of the first wire

3x---> the length of the second wire

2(3x)=6x -----> the length of the third wire

Part a) WRITE AN *INEQUALITY* THAT MODELS THE SITUATION

we know that

The inequality that represent the situation is

x+(3x)+(6x) \leq 350

Part b) WHAT ARE THE POSSIBLE LENGTHS OF THE SHORTEST PIECE OF WIRE?

we know that

The shortest piece of wire is the first wire

so

Solve the inequality

x+(3x)+(6x) \leq 350

10x \leq 350

x \leq 35\ in

The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to 35\ inches

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mrs_skeptik [129]

Answer:

first find the surface area of one of the square and one of the triangle.

then multiple it by the number of square and triangle they have

finally add the total surface area of the triangle with the total surface area of the square.

Step-by-step explanation:

  1. for one square

area= base * width

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total area of square= number of square * area of one square

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area = 1/2 base * height

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total area of triangle=number of triangle* area of one triangle

t2=8*43.3

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=600+346.4

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Answer:

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Step-by-step explanation:

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