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Elanso [62]
3 years ago
5

Raymond wants to make a box that has a volume of 360 cubic inches. He wants the height to be 10 inches and the other two dimensi

ons to be whole numbers of inches. How many different-sized boxes can he make?
Mathematics
2 answers:
Sauron [17]3 years ago
8 0
It depends on what the units are measured
Ghella [55]3 years ago
3 0
3 because 360/10 =36 so you have to find factors of 36 (not sure if factors is the right word) but they are :3&12,9&4,6&6
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A restaurant chain has two locations in a medium-sized town and, believing that it has oversaturated the market for its food, is
scoray [572]

Answer:

Yes, since the test statistic value is greater than the critical value.

Step-by-step explanation:

Data given and notation

\bar X_{1}=360000 represent the mean for the downtown restaurant

\bar X_{2}=340000 represent the mean for the freeway restaurant

s_{1}=50000 represent the sample standard deviation for downtown

s_{2}=40000 represent the sample standard deviation for the freeway

n_{1}=36 sample size for the downtown restaurant

n_{2}=36 sample size for the freeway restaurant

t would represent the statistic (variable of interest)

\alpha=0.05 significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the true mean of revenue for downtown is higher than for freeway restaurant, the system of hypothesis would be:

Null hypothesis:\mu_{1}\leq \mu_{2}

Alternative hypothesis:\mu_{1} > \mu_{2}

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Determine the critical value.

Based on the significance level\alpha=0.05 and \alpha/2=0.025 we can find the critical values from the t distribution dith degrees of freedom df=36+36-2=55+88-2=70, we are looking for values that accumulates 0.025 of the area on the right tail on the t distribution.

For this case the value is t_{1-\alpha/2}=1.66

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

t=\frac{360000-340000}{\sqrt{\frac{50000^2}{36}+\frac{40000^2}{36}}}}=1.874

What is the p-value for this hypothesis test?

Since is a right tailed test the p value would be:

p_v =P(t_{70}>1.874)=0.033

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the true mean for the downtown revenue restaurant seems higher than the true mean revenue for the freeway restaurant.

The best option would be:

Yes, since the test statistic value is greater than the critical value.

5 0
2 years ago
Is the answer 3, 4, 5, or 6? need answer asap please! :)
-BARSIC- [3]
Don't touch the center. It is already even. 
Start anywhere by connecting a dotted line from one vertex to the next. To keep things so we know what we are talking about, go clockwise. Now you have 2 points that are Eulerized that were not before.

Skip and edge and do the same thing to the next two vertices. Those two become eulerized. Skip an edge and do the last 2.

Let's try to describe this better. Start at any vertex and number them 1 to 6 clockwise.
Join 1 to 2 
Join 3 to 4
Join 5 to 6

I think 3 is the minimum.
3 <<<< answer
4 0
3 years ago
Help me please thanks before
sdas [7]
-17 + 28 = 11

hope this helps, give brainliest 
8 0
3 years ago
Read 2 more answers
David is going to invest $330 and leave it in an account for 20 years. Assuming the
Cerrena [4.2K]

Answer:

$1255.

Step-by-step explanation:

Mark me brainlest!

3 0
3 years ago
When mrs. myles gave a test, the scores were normally distributed with a mean of 72 and a standard deviation of 8. this means th
irina [24]
The empirical rule states that in a normal distribution,
68% of data is within 1 std deviation of the mean
95%  of data is within 2 std deviation of the mean
99.7% of data is within 3 std deviation of the mean

In this case 95% of the cases would be within two std deviations of the mean 
    mean - 8         and    mean + 8
     72   - 8 = 64   and    72 + 8 = 80 

then 95% of the scores are between  64% and 80% on the test. 
5 0
3 years ago
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