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Elanso [62]
3 years ago
5

Raymond wants to make a box that has a volume of 360 cubic inches. He wants the height to be 10 inches and the other two dimensi

ons to be whole numbers of inches. How many different-sized boxes can he make?
Mathematics
2 answers:
Sauron [17]3 years ago
8 0
It depends on what the units are measured
Ghella [55]3 years ago
3 0
3 because 360/10 =36 so you have to find factors of 36 (not sure if factors is the right word) but they are :3&12,9&4,6&6
You might be interested in
Using the functions f(x) = (3 - x)/(x2 + 4) and g(x) = 3x, find the value of (f*g)(2).
wariber [46]

9514 1404 393

Answer:

  (f×g)(2) = 3/4

Step-by-step explanation:

For each of the functions, put 2 where x is and evaluate the expression.

  f(2) = (3 -2)/(2² +4) = 1/8

  g(2) = 3×2 = 6

Then the product is ...

  (f×g)(2) = f(2)×g(2) = (1/8)×6 = 6/8

  (f×g)(2) = 3/4

4 0
2 years ago
It is known that the life of a particular auto transmission follows a normal distribution with mean 72,000 miles and standard de
scoray [572]

Answer:

a) P(X

P(z

b) P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

P(z>-0.583)=1-P(Z

c) P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

d) z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the life of a particular auto transmission of a population, and for this case we know the distribution for X is given by:

X \sim N(72000,12000)  

Where \mu=72000 and \sigma=12000

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using excel or the normal standard table and we got:

P(z

Part b

P(X>65000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>-0.583)=1-P(Z

Part c

P(X>100000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

Part d

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

5 0
3 years ago
“the perimeter of the rectangle below is 90 units. find the length of side PS. write your answer without variables.”
Rzqust [24]

Answer:

19

Step-by-step explanation:

The opposite sides are equal, so:

PS = 3y+1

RS = 4y+2

QR = 3y+1

PQ = 4y+2

Therefore, we can set the perimeter 90 = PS+RS+QR+PQ

90 = (3y+1) + (4y+2) + (3y+1) + (4y+2), or,

90 = 2(3y+1) + 2(4y+2)

90 = 6y+2 + 8y+4

90 = 14y + 6

84 = 14y

y = 6

Then, we go back to the question. It's asking for the length of PS. PS = 3y+1, so we plug in 6 for y

3(6)+1

18 + 1 = <u>19</u>

5 0
3 years ago
Rebecca is planting an orange grove that covers 32 acres she uses the same amount of ground space for each tree Rebecca plants 1
telo118 [61]
Area of the garden that 15 trees are planted will be:
Area=250×25=6250 ft²
but 1 acre= 43560 ft²
thus converting our area to acres we get:
6250/(43560)
=0.1435 acres
thus the population density will be:
(Population)/(area)
=15/0.1435
=104.544 trees/acre
4 0
2 years ago
Helppp plzzzz, it’s 3:06 pm and this due 3:25 (eastern) time .
Murljashka [212]

Answer:

y=0,25x

Step-by-step explanation:

1×0,25=0,25

2×0,25=0,5

3×0,25=0,75

4×0,25=1,0

5×0,25=1,5

hope it'll help you dude

8 0
3 years ago
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