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3 years ago

What is the interquartile range of this box plot? And how do you find it?

Mathematics

1 answer:

Alik [6]3 years ago

4 0

Answer:

Step-by-step explanation:

Calculate the median, which is the middle number of an ordered range with an odd number. 3.

Calculate the medians of the bottom and top halves, omitting the middle number. Since these are now even-numbered sets, we'll take the average of the middle two numbers of each. Lower is 1.5, upper is 4.5.

Calculate the difference of the upper median and lower median, so 4.5 - 1.5 = 3.

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If 3x - 3y = 9 and x + y = 5. then x equals...?

Gwar [14]

Answer: x = 4

Step-by-step explanation:

x + y = 5

y = 5 - x

3x - 3y = 9

=> 3x - 3(5-x) = 9

=> 3x - 15 + 3x = 9

=> 6x = 24

=> x = 4

5 0

3 years ago

-1/13-10/39 please solve for me I dont seem to get it

natima [27]

Answer:

$\frac{-1}{3}$

Step-by-step explanation:

$\frac{-1}{13} - \frac{10}{39}$

Find common denominator for 13 and 39

common denominator is 39

rewrite fractions so they have the same denominator

$\frac{-1}{13} = \frac{-3}{39}$

add them up

$\frac{-3}{39} + \frac{-10}{39} = \frac{-13}{39}$

simplify/ put in the lowest terms

$\frac{-1}{3}$

5 0

3 years ago

Hurry im despret i need help

svp [43]

The slope-point form of line:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (-9, 7) and (6, 2). Substitute:

$m=\dfrac{2-7}{6-(-9)}=\dfrac{-5}{6+9}=-\dfrac{5}{15}=-\dfrac{1}{3}\\\\y-7=-\dfrac{1}{3}(x-(-9))\\\\\boxed{y-7=-\dfrac{1}{3}(x+9)}$

The slope-intercept form of line:

$y=mx+b$ .

We have the slope m:

$y=-\dfrac{1}{3}x+b$

Pu the coordinates of the point (6, 2) to the equation:

$2=-\dfrac{1}{3}(6)+b$

$2=-2+b$ <em>add 2 to both sides</em>

$4=b\to b=4$

$\boxed{y=-\dfrac{1}{3}x+4}$

6 0

3 years ago

No chi-square The principal in Exercise 7 also

larisa [96]

The random sample of the students is an illustration of sampling

The chi-square test for goodness of fit is inappropriate because the variable under study is not categorical.

<h3>How to determine the reason chi square is not appropriate?</h3>

The dataset is given as:

Monday 34

Tuesday 29

Wednesday 32

Thursday 28

Friday 19

The variable of the above dataset is a not a categorical dataset.

One of the conditions of the chi-square test for goodness of fit test is that the variable under study must be categorical.

Hence, the chi-square test for goodness of fit is inappropriate because the variable under study is not categorical.