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erastovalidia [21]
2 years ago
14

Help Me on this!!

%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20" id="TexFormula1" title=" \: \: \: \: \: \: \: \: \: \: \: \: " alt=" \: \: \: \: \: \: \: \: \: \: \: \: " align="absmiddle" class="latex-formula">


​

Mathematics
1 answer:
cricket20 [7]2 years ago
7 0

\qquad\qquad\huge\underline{{\sf Answer}}

Here's the solution :

9. Statement : \tt{VB\:\: bisects\;\; \angle EVO}

  • Reason : \tt Given

10. Statement :\tt \angle3 \cong \angle 4

  • Reason : \tt Definition \;\; of \;\; angle \;\; bisector

11. Statement \tt{VB\:\: bisects\;\; \angle EBO}

  • Reason : \tt Given

12. Statement :\tt \angle1 \cong \angle 2

  • Reason : \tt Definition \;\; of \;\; angle \;\; bisector

13. Statement : \tt \overline{BV }\cong \overline{BV}

  • Reason : \tt Common\:\: side

14. Statement : \tt \triangle \:BEV \cong \triangle \:BOV

  • Reason : \tt ASA \:\: postulate

15. Statement : \tt \angle E \cong \angle O

  • Reason : \tt Corresponding\;\;parts\:\: of\:\: Congruent \;\;Triangles
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Can someone help me I’m a little lost
Ksivusya [100]

Answer:

14 days

Step-by-step explanation:

Total Problems = 175

Finished Problems = 8

Remaining = 175 - 8 = 167

8 problems in 30 minutes, means:

30/8 = 15/4 = 3.75 minutes per problem

If he works for 45 minutes, at that rate, he can solve:

45/3.75 = 12 problems per day

To finish 167 problems, he will need:

167/12 = 13.91

Rounded, that is <u>14 days more to finish</u>

8 0
4 years ago
What’s the inverse equation?
algol [13]

Answer:

The inverse is ((5-x)/4) ^ 1/3

Step-by-step explanation:

y = 5-4x^3

Exchange x and y

x = 5-4y^3

Subtract 5 from each side

x-5 =5-5-4y^3

x-5 = -4y^3

Divide each side by -4

(x-5)/ -4 = y^3

Take the cube root

((x-5)/ -4) ^ 1/3 = y^ 3 ^1/3

((5-x)/4) ^ 1/3 = y

The inverse is ((5-x)/4) ^ 1/3

4 0
3 years ago
Frank ate 12 pieces of pizza and Dave ate 15 pieces. “I ate
kobusy [5.1K]

Answer:

Frank

Step-by-step explanation:

So If Dave ate ¼ more than Frank, you would need to divide the denominator by the amount of pizzas, so if 12÷4 is 3 he ate three more pizzas than Frank. If we do the same for Frank, ⅕ or 15÷5=3

So the correct answer would be Frank because 12 is less than 15

My apologies if this wasnt explained very well

7 0
4 years ago
Two examples of hundreds place
kaheart [24]
0.987
8 is in the hundredths

0.45
5 is in the hundredths
7 0
4 years ago
Exposure to microbial products, especially endotoxin, may have an impact on vulnerability to allergic diseases. The following ar
Softa [21]

Answer:

A. E ( U ) = 21.5454  , E ( F ) = 8.39333

B. M ( U ) =  17.0 , M ( F ) =  18.0

C. E ( U' ) = 17.0  , E ( F' ) = 7.95384

D. T ( U ) = 9.091% , T ( F ) = 6.667%

Step-by-step explanation:

Solution:-

- Two sample sets ( U ) and ( F ) that define the concentration ( EU/mg ) of endotoxin found in urban and farm homes as follows:

             U: 6.0 5.0 11.0 33.0 4.0 5.0 80.0 18.0 35.0 17.0 23.0

             F: 2.0 15.0 12.0 8.0 8.0 7.0 6.0 19.0 3.0 9.8 22.0 9.6 2.0 2.0 0.5

- To determine the mean of a sample E ( U ) or E ( F ) the following formula from descriptive statistics is used:

                         E ( X ) = Sum ( X_i ) / n

Where,

                         Xi : Data iteration

                         n: Sample size

Therefore,

                            E ( U ) =  \frac{Sum (U_i )}{n_u} \\\\E ( U ) =  \frac{6.0 + 5.0 + 11.0 + 33.0 + 4.0+ 5.0 +80.0+ 18.0+ 35.0+ 17.0+ 23.0 }{11} \\\\E ( U ) = 21.54545\\\\E ( F ) =  \frac{Sum (F_i )}{n_f} \\\\E ( F ) =  \frac{2.0 + 15.0 + 12.0 + 8.0 + 8.0 + 7.0 + 6.0 + 19.0+ 3.0+ 9.8+ 22.0+ 9.6+ 2.0+ 2.0+ 0.5 }{15} \\\\E ( F ) = 8.39333      

- To determine the sample median we need to arrange the data for both samples ( U ) and ( F ) in ascending order as follows:

             U: 4.0 5.0 5.0 6.0 11.0 17.0 18.0 23.0 33.0 35.0 80.0

             F: 0.5 2.0 2.0 2.0 3.0 6.0 7.0 8.0 8.0 9.6 9.8 12.0 15.0 19.0 22.0

- Now find the mid value for both sets:

            Median term ( U ) = ( n + 1 ) / 2  

                                          = ( 11 + 1 ) / 2 = 12/2 = 6th term

            Median ( U ), 6th term = 17.0

            Median term ( F ) = ( n + 1 ) / 2  

                                          = ( 15 + 1 ) / 2 = 16/2 = 8th term

            Median ( F ), 8th term = 8.0

- We will now trim the smallest and largest observation from each set.

- In set ( U ) we see that smallest data corresponds to ( 4.0 ) while the largest data corresponds to ( 80.0 ). We will exclude these two terms and the trimmed set is defined as:

              U': 5.0 5.0 6.0 11.0 17.0 18.0 23.0 33.0 35.0

- In set ( F ) we see that the smallest data corresponds to ( 0.5 ) while the largest data corresponds to ( 22.0 ). We will exclude these two terms and the trimmed set is defined as:

              F': 2.0 15.0 12.0 8.0 8.0 7.0 6.0 19.0 3.0 9.8 9.6 2.0 2.0

- We will again use the previous formula to calculate means of trimmed samples ( U' ) and ( F' ) as follows:

              E ( U' ) = \frac{5.0+ 5.0+ 6.0+ 11.0+ 17.0+ 18.0+ 23.0+ 33.0+ 35.0}{9} \\\\E ( U' ) = 17

              E ( F' ) = \frac{2.0 +2.0+ 2.0 +3.0+ 6.0+ 7.0+ 8.0+ 8.0+ 9.6+ 9.8+ 12.0+ 15.0+ 19.0}{13} \\\\E ( F' ) = 7.95384    

- The trimming percentage is known as the amount of data removed from the original sample from top and bottom of sample size of 11 and 15, respectively.

- We removed the smallest and largest value from each set. Hence, a single value was removed from both top and bottom of each data set. We can express the trimming percentage for each set as follows:

                  T ( U ) = \frac{1}{11} * 100 = 9.091\\\\T ( F ) =  \frac{1}{15} * 100 = 6.667%

- The trimming pecentages for each data set are 9.091% and 6.667% respectively.

7 0
4 years ago
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