Question

A ship drops anchor in a harbor. The anchor is 49 ft. above the surface of the water when it is

Answer 1

Answer:

b

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

h = -16t² + vt + s

v is the starting velocity, and s is the starting height.

a. The starting height is 49 feet.

s = 49

b. When the anchor hits the water, the height is 0.

h = 0

c. Plug in values:

0 = -16t² + 0t + 49

0 = -16t² + 49

16t² = 49

t² = 49/16

t = 7/4