Please say all that apply
1 answer:
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Answer:
The height of the water = 6.2 in. to the nearest tenth
Step-by-step explanation:
∵ The rate of flows of water into the tank = 8000 in.³/min.
∴ The volume of the water in the tank after 10 min. = 8000 × 10 = 80000 in.³
∵ The water take the shape of the tank
∴ The height of the water = volume of water ÷ Area of the base of the tank
∵ The tank is cylinder with diameter 128 in. and height 72 in.
∴ The area of the base of the tank = π(128/2)²
∴ The height of the water =
∴ The height of the water = 6.2 in. to the nearest tenth
Answer: c.(3, 25) and (7, 9)
y = –x^2 + 6x + 16 and y = –4x + 37
Plug in -4x+37 for y in first equation . It becomes
Combine like terms. add 4x and subtract 37 on both sides
Divide the whole equation by -1 to remove negative sign from -x^2
Now factor the left hand side
(x-7)(x-3) = 0
x-7 =0 and x-3=0
x= 7 and x=3
Now we find out y using y = –4x + 37
when x= 7 , then y=-4(7) +37 = 9
when x= 3, then y=-4(3) + 37 = 25
We write solution set as (x,y)
(7,9) and (3,25) is our solution set