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Anettt [7]
3 years ago
13

Estimate 79% of 16 by rounding the percent to the closest whole number percent and the quantity to the closest whole number

Mathematics
2 answers:
Reptile [31]3 years ago
5 0

Answer:

13.43

Step-by-step explanation:

i used a percentage calculator

erastovalidia [21]3 years ago
4 0

Answer:

12.64

Step-by-step explanation:

I Hope this is right first answer ever

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In a recent year the fuel economy of all passenger vehicles was 19.8 mpg. A trade organization sampled 50 passenger vehicles for
salantis [7]

Answers and Step-by-step explanation:

Hypotheses are:

H o=19.8

H 1 ≠19.8

Here we have following information:

s=2.45, X bar=20.1, n=50

So test statistics will be

t=20.1-19.8/(2.45/\sqrt{50} =0.87

Degree of freedom : d f = n - 1 = 50 - 1 =49

Test is two tailed so critical value of the test is -1.30 and 1.30.

Rejection region:

if t < -1.30 and t > 1.30, reject H o

Since test statistics lie in the rejection region so we fail to reject the null hypothesis.

(b)

The observed significance of the test is

P value =0.3885

(c)

Since p value is greater than 0.20 so we fail to reject the null hypothesis.

5 0
3 years ago
Jim and Jackie are married with three children at home and a mortgage. Jim’s net pay per year is $67,000 and Jackie does not hav
Darya [45]
The answer is A. they should work on their plan for managing income. 
4 0
4 years ago
Read 2 more answers
If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.
Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have S_1=3\times2^{1-1}+2(-1)^1=3-2=1, which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}

and

S_k=3\times2^{k-1}+2(-1)^k

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}

From the given recurrence, we know

S_{k+1}=S_k+2S_{k-1}

so that

S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)

S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}

S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)

S_{k+1}=3\times2^k-2(-1)^k

S_{k+1}=3\times2^k+2(-1)(-1)^k

\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}

which is what we needed. QED

6 0
3 years ago
Given the equation
tatiyna

Answer:

A. Subtract x from both sides: (i.e. 5+x-12 = x-7 <--> 5-12 = -7)

This equation is identically true, so it holds no matter what x is.

B. This one is pretty self-explanatory

Step-by-step explanation:

u wrote the question wrongly the answer is in answer box

This question also my teacher gives me

hope it helps

8 0
3 years ago
What is the answer for -5x-8=3x+10
SIZIF [17.4K]

Answer:

x=− 9 /4

​or  

=−2.250

Step-by-step explanation:

4 0
3 years ago
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