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Ainat [17]
3 years ago
15

26. A theater has 20 seats in first row, 22 in second row, 24 in third row and

Mathematics
1 answer:
spayn [35]3 years ago
6 0

Answer:

38 seats

Step-by-step explanation:

if the seat numbers are going up by 2 more seats in each rows like the pattern was showing us with the numbers 20,22,24 then if you keep counting to 30 for the rows then you would get 38 seat in row 30

sorry if this doesnt make any sense!!

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Find the standard form polynomial that represents this product. (6 - y - 4y^2)(-5 + 7y^2)​
Tema [17]

Answer:

  • -28y^4 - 7y^3 + 62y^2 + 5y - 30

Step-by-step explanation:

<u>Opening the parenthesis and simplifying by combining like terms:</u>

  • (6 - y - 4y^2)(-5 + 7y^2)​  =
  • 6(-5) +6(7y^2) - y(-5) -y(7y^2) -4y^2(-5) -4y^2(7y^2) =
  • -30 + 42y^2  + 5y - 7y^3 +20y^2 -28y^4 =
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5 0
3 years ago
2.- Supóngase que los diámetros de los tornillos fabricados por una compañía están distribuidos normalmente con una media de 0.2
Sergio [31]

Answer:

7.30167%

Step-by-step explanation:

Usando la fórmula de puntuación z

z = (x-μ) / σ, donde x es la puntuación bruta, μ es la media de la población y σ es la desviación estándar de la población

Para x <0.20 pulgadas

z = 0.20 - 0.25 / 0.02

z = -2.5

Valor de probabilidad de Z-Table:

P (x <0.20) = 0.0062097

Para x> 0.28 pulgadas

z = 0.28 - 0.20 / 0.02

z = 1.5

Valor de probabilidad de Z-Table:

P (x <0.28) = 0.93319

P (x> 0.28) = 1 - P (x <0.28) = 0.066807

La probabilidad de que se produzcan tornillos defectuosos cuando el tornillo se considera defectuoso si su diámetro es inferior a 0.20 pulgadas o superior a 0.28 pulgadas es

P (x <0.20) + P (x> 0.28)

= 0.0062097 + 0.066807

= 0.0730167

Conversión a porcentaje

= 0.0730167 × 100

= 7.30167%

El porcentaje de tornillos defectuosos producidos es

7.30167%

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2 years ago
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Answer:

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Step-by-step explanation:

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