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Aliun [14]
3 years ago
14

Create a function named test2Problem2that contains a list comprehension. This function will take asingle integer parameter nand

returns a list of length n of every other prime. (Please note that primes start at 2.)There will be a 10 point deduction for not using a list comprehension to solve this problem.List comprehensions have this form: [ expression for item in list if conditional ]In:10Out:[2,5,11,17,23,31,41,47,59,67]In:7Out:[2,5,11,17,23,31,41]
Computers and Technology
1 answer:
ikadub [295]3 years ago
3 0

Answer:

C++.

Explanation:

#include <iostream>

using namespace std;

/////////////////////////////////////////////////////////

void printPrime(int n) {

   if (n > 0) {

       cout<<"[2";

       for (int i=3; i<=n; i++) {

           bool isPrime = true;

           

           for (int j=2; j<i; j++) {

               if (i % j == 0) {

                   isPrime = false;

                   break;

               }

           }

           

           if (isPrime == true)

               cout<<", "<<i;

       }

   }

   else {

       cout<<"Invalid input";

   }

   cout<<"]";

}

/////////////////////////////////////////////////////////

int main() {

   int n;

   cout<<"Enter positive integer: ";

   cin>>n;

   printPrime(n);

   return 0;

}

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Assume that ip has been declared to be a pointer to int and that enrollment has been declared to be an array of 20 elements . As
Vitek1552 [10]

Answer:

ip = enrollment + section;

Explanation:

The variable ip has been declared to be a pointer to int.

int * ip;

The variable enrollment has been declared as an array of 20 elements .

int enrollment[20];

The variable section has been declared as an int.

int section;

In order to make ip point to the element in the array indexed by section, we can use the following statement :

ip = enrollment + section;

This will make ip point to enrollment[section].

5 0
3 years ago
Modern ssds use a technique called "____" to spread write operations around the storage medium, thus evening out the impact of d
masha68 [24]

The question above has multiple choices as below;

<span>a.      </span>Wear aggregation.

<span>b.      </span>Wear mitigation.

<span>c.      </span>Wear prevention

<span>d.      </span>Wear leveling

The answer is d) Wear leveling.


This technique by some SSD controllers to increase the memory’s lifetime is called wear leveling. The mechanism for this principle is simple: distribute the entries for all the blocks evenly so that they will wear out evenly. Flash controller typically manages wear leveling and uses a wear leveling algorithm to control which physical block to use.







7 0
3 years ago
Suppose you have two arrays of ints, arr1 and arr2, each containing ints that are sorted in ascending order. Write a static meth
telo118 [61]
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.

public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}


So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.

A quick explanation:

We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.

The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.


4 0
3 years ago
A ____________________ can be used to hierarchically represent a classification for a given set of objects or documents. A. taxo
neonofarm [45]

Answer:

A. taxonomy

Explanation:

A taxonomy can be used to hierarchically represent a classification for a given set of objects or documents.

3 0
3 years ago
Write a program with a car's miles/gallon and gas dollars/gallon (both floats) as input, and output the gas cost for 10 miles, 5
omeli [17]

Answer:

The Following are the code to this question:

def cost(miles, milesPerGallon, dollarsPerGallon):##defining a method cost that accepts three parameter

   return miles / milesPerGallon * dollarsPerGallon# calculate cost and return it value  

milesPerGallon = float(input('Enter miles/Gallon value: '))#defining variable milesPerGallon for user input  

dollarsPerGallon = float(input('Enter dollars/ Gallon value: '))#defining variable dollarsPerGallon for user input

print('{:.5f}'.format(cost(10, milesPerGallon, dollarsPerGallon)))#call method and print its value

print('{:.5f}'.format(cost(50, milesPerGallon, dollarsPerGallon)))#call method and print its value

print('{:.3f}'.format(cost(400, milesPerGallon, dollarsPerGallon)))#call method and print its value

Output:

Enter miles/Gallon value: 20.0

Enter dollars/ Gallon value: 3.1599

1.57995

7.89975

63.198

Explanation:

In the above-given code, a method "cost" is defined, that accepts three value "miles, milesPerGallon, and dollarsPerGallon" in its parameter, and use the return keyword for calculating and return its value.

In the next step, two variable "milesPerGallon, and dollarsPerGallon" is declared, that use the input method with float keyword for input floating-point value.

After input value, it uses a print method with different miles values, which are "10,50, and 400", and input value to pass in cost method to call and print its return value.

5 0
3 years ago
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