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Aliun [14]
3 years ago
14

Create a function named test2Problem2that contains a list comprehension. This function will take asingle integer parameter nand

returns a list of length n of every other prime. (Please note that primes start at 2.)There will be a 10 point deduction for not using a list comprehension to solve this problem.List comprehensions have this form: [ expression for item in list if conditional ]In:10Out:[2,5,11,17,23,31,41,47,59,67]In:7Out:[2,5,11,17,23,31,41]
Computers and Technology
1 answer:
ikadub [295]3 years ago
3 0

Answer:

C++.

Explanation:

#include <iostream>

using namespace std;

/////////////////////////////////////////////////////////

void printPrime(int n) {

   if (n > 0) {

       cout<<"[2";

       for (int i=3; i<=n; i++) {

           bool isPrime = true;

           

           for (int j=2; j<i; j++) {

               if (i % j == 0) {

                   isPrime = false;

                   break;

               }

           }

           

           if (isPrime == true)

               cout<<", "<<i;

       }

   }

   else {

       cout<<"Invalid input";

   }

   cout<<"]";

}

/////////////////////////////////////////////////////////

int main() {

   int n;

   cout<<"Enter positive integer: ";

   cin>>n;

   printPrime(n);

   return 0;

}

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Answer:

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Explanation:

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3 years ago
What's the drawback of using Screened Subnet (DMZ)?
lesantik [10]

It's more expensive, it's more difficult to configure and maintain and it can be more difficult to troubleshoot

4 0
4 years ago
Write a program that simulates flipping a coin repeatedly and continues until three consecutive heads. are tossed. At that point
quester [9]

Answer and Explanation:

#include <iostream>

#include <string>

#include <time.h>

#include <vector>

using namespace std;

//Takes user info

int user_info(string *name,char *gender){

   char G;

   cout<<"What is your name?: ";

   getline(cin, *name);

   cout<<"What is your gender(m/f):";

   cin>>G;

   cout<<endl;

   *gender = tolower(G);

   return 0;

}

//Toss coin(part 2)

bool coin_toss(double seed){

   double r;

   r = (double)seed/(double)RAND_MAX;

   //cout<<r;

   if (r<0.5) return true;

   return false;

}

//check results

float toss_result(vector<char> v,int *h){

   int num_heads=0;

   int num_toss = v.size();

   *h = 0;

   for(int i=0;i<num_toss;i++){

       if(v[i]=='h'){num_heads++;(*h)++;}

   }

   return (float)num_heads/(float)num_toss;

}

void show_result(int total_num,int head_num,float ratio){

   cout<<"it took you "<<total_num<<" tosses to get 3 heads in a row"<<endl;

   cout<<"on average you flipped heads "<<(ratio*100)<<"% of the time"<<endl;

}

int main()

{

   string name;

   char gender;

   string K; //Mr or Mrs

 

   cout<<"Welcome to coin toss! Get 3 heads in row to win!"<<endl;

 

   //part 1

   user_info(&name,&gender);

 

   if(gender == 'f') K = "Mrs.";

   else K = "Mr.";

 

   cout<<"Try to get 3 heads in a row. Good luck "<<K<<name<<"!"<<endl;

   char dummy = getchar();

 

   //part 2

   int num_toss;

   vector<char> toss_results;//store toss results

   bool result;//result of toss

   srand(time(0));

   while(true){

       //cout<<rand()<<endl;

       result = coin_toss(rand());

       cout<<"Press <enter> to flip"<<endl;

       while (1)

       {

           if ('\n' == getchar())

           break;

       }

     

 

     

       if(result) {toss_results.push_back('h');cout<<"HEAD"<<endl;}

       else {toss_results.push_back('t');cout<<"TAIL"<<endl;}

     

       num_toss = toss_results.size();

     

       if(num_toss>=3){

           if ((toss_results[num_toss-1] == 'h')&&(toss_results[num_toss-2] == 'h')&&(toss_results[num_toss-3] == 'h')){

               break;

           }

       }

   }

 

   //part 3

   float ratio_head;

   int num_of_heads;

   ratio_head = toss_result(toss_results,&num_of_heads);

 

   //part 4

 

   show_result(toss_results.size(),num_of_heads,ratio_head);

 

   return 0;

}

8 0
3 years ago
1. Write a high level algorithm for cooking a cheeseburger.
pishuonlain [190]

Answer:

1.  A high level algorithm for cooking a cheeseburger could be:

  1. Heat fry pan
  2. Cook one side of the hamburger
  3. Wait
  4. Turn hamburger upside down
  5. Put cheese over hamburger
  6. Wait
  7. Cut hamburger bread in half
  8. Put cooked hamburger inside bread
  9. End (eat)

2. A detailed algorithm for cooking a cheeseburger could be:

  1. Place fry pan over the stove heater
  2. Turn on heater (max temp)
  3. IF fry pan not hot: wait, else continue
  4. Place raw hamburger on fry pan
  5. IF hamburger not half cooked: Wait X time then go to line 5, else continue
  6. Turn hamburger upside down
  7. Put N slices of cheese over hamburger
  8. IF hamburger not fully cooked: Wait X time then go to line 8, else continue
  9. Turn off heater
  10. Cut hamburger bread in half horizontally
  11. Put cooked hamburger on one of the bread halves.
  12. Put second bread half on top of hamburger
  13. End (eat)

Explanation:

An algorithm is simply a list of steps to perform a defined action.

On 1, we described the most relevant steps to cook a simple cheeseburger.

Then on point 2, the same steps were taken and expanded with more detailed steps and conditions required to continue executing the following steps.

In computational terms, we used pseudo-code for the algorithm, since this is a list of actions not specific to any programming language.

Also we can say this is a structured programming example due to the sequential nature of the cooking process.

7 0
3 years ago
A variable like userNum can store a value like an integer. Extend the given program to print userNum values as indicated.(1) Out
dimulka [17.4K]

Answer:

The program in Java is as follows:

import java.util.*;

public class Main{

public static void main(String[] args) {

 int userNum;

 Scanner input = new Scanner(System.in);

 System.out.print("Enter integer: ");

 userNum = input.nextInt();

 System.out.println("You entered "+userNum);

 System.out.println(userNum+" squared is "+(userNum*userNum));

 System.out.println(userNum+" cubed is "+(userNum*userNum*userNum));

 int userNum2;

 System.out.print("Enter another integer: ");

 userNum2 = input.nextInt();

 int sum= userNum + userNum2; int product = userNum2 * userNum;

 System.out.println(userNum+" + "+userNum2+" = "+sum);

 System.out.println(userNum+" * "+userNum2+" = "+product); } }

Explanation:

This declares userNum

 int userNum;

 Scanner input = new Scanner(System.in);

This prompts the user for input

 System.out.print("Enter integer: ");

This gets user input from the user

 userNum = input.nextInt();

Number (1) is implemented here

 System.out.println("You entered "+userNum);

Number (2) is implemented here

 System.out.println(userNum+" squared is "+(userNum*userNum));

 System.out.println(userNum+" cubed is "+(userNum*userNum*userNum));

This declares another variable userNum2

 int userNum2;

This prompts the user for another input

 System.out.print("Enter another integer: ");

This gets user input from the user

 userNum2 = input.nextInt();

This calculates the sum and the product

 int sum= userNum + userNum2; int product = userNum2 * userNum;

Number (3) is implemented here

 System.out.println(userNum+" + "+userNum2+" = "+sum);

 System.out.println(userNum+" * "+userNum2+" = "+product);

8 0
3 years ago
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