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Ksenya-84 [330]

3 years ago

15

Joe's workout at the gym was a total of 90 minutes. If he spent 1/3 of the time lifting weights, how much time did he have left

to run on the treadmill?

1 answer:

atroni [7]3 years ago

5 0

Answer:

60 minutes, or 1 hour.

Step-by-step explanation:

90 minutes ÷ 3 = 30 minutes, so 30 minutes equals 1 third of the total time he spent at the gym, and he lifted weights for 30 minutes. The remaining 2 thirds, 60 minutes, is the time he spent on the treadmill.

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Could y’all help me out with this?

Aneli [31]

Answer:

M' (5,-1)

D' (5,1)

A' (3,4)

W' (4,-1)

Step-by-step explanation:

We want to find the coordinates of Quadrilateral MDAW with vertices M(-1, 5), D(1,5), A(4,3), and W(-1,4) after a reflection across y = x.

We can find these coordinates by following the following rule:

Reflection over y = x rule : ( x , y ) ---> ( y , x )

Explanation of rule: Simply swap the places of the x and y values.

Applying rule to given coordinates:

M(-1,5) -----> swap x and y values -----> M'(5,-1)

D(1,5) ----> swap x and y values -----> D'(5,1)

A(4,3) -----> swap x and y values -----> A'(3,4)

W(-1,4) -----> swap x and y values -----> W'(4,-1)

So the coordinates of Quadrilateral MDAW after a reflection over the y = x line are M'(5,-1) , D'(5,1) , A'(3,4) , W'(4,-1)

For more validation, refer to the attached image

4 0

3 years ago

Consider the function represented by 9x+3y= 12 with x as the independent variable. How can this function be written using

Ivenika [448]

Answer:

f(x)=-3x+4

(can't see some of your choices)

Step-by-step explanation:

We want x to be independent means we want to write it so when we plug in numbers we can just choose what we want to plug in for x but y's value will depend on our choosing of x.

So we need to solve for y.

9x+3y=12

Subtract 9x on both sides

3y=-9x+12

Divide both sides by 3:

y=-3x+4

Replace y with f(x).

f(x)=-3x+4

6 0

3 years ago

Hi everyone i got a 16/20 on a final what percent is that im jw

Allushta [10]

Answer:

80%

Step-by-step explanation:

5 0

3 years ago

Time spent using e-mail per session is normally distributed, with mu equals 11 minutes and sigma equals 3 minutes. Assume that

liq [111]

Answer:

a) 0.259

b) 0.297

c) 0.497

Step-by-step explanation:

To solve this problem, it is important to know the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 11, \sigma = 3$

a. If you select a random sample of 25 sessions, what is the probability that the sample mean is between 10.8 and 11.2 minutes?

Here we have that $n = 25, s = \frac{3}{\sqrt{25}} = 0.6$

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{11.2 - 11}{0.6}$

$Z = 0.33$

$Z = 0.33$ has a pvalue of 0.6293.

X = 10.8

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.8 - 11}{0.6}$

$Z = -0.33$

$Z = -0.33$ has a pvalue of 0.3707.

0.6293 - 0.3707 = 0.2586

0.259 probability, rounded to three decimal places.

b. If you select a random sample of 25 sessions, what is the probability that the sample mean is between 10.5 and 11 minutes?

Subtraction of the pvalue of Z when X = 11 subtracted by the pvalue of Z when X = 10.5. So

X = 11

$Z = \frac{X - \mu}{s}$

$Z = \frac{11 - 11}{0.6}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

X = 10.5

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.5 - 11}{0.6}$

$Z = -0.83$

$Z = -0.83$ has a pvalue of 0.2033.

0.5 - 0.2033 = 0.2967

0.297, rounded to three decimal places.

c. If you select a random sample of 100 sessions, what is the probability that the sample mean is between 10.8 and 11.2 minutes?

Here we have that $n = 100, s = \frac{3}{\sqrt{100}} = 0.3$

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{11.2 - 11}{0.3}$

$Z = 0.67$

$Z = 0.67$ has a pvalue of 0.7486.

X = 10.8

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.8 - 11}{0.3}$

$Z = -0.67$

$Z = -0.67$ has a pvalue of 0.2514.

0.7486 - 0.2514 = 0.4972

0.497, rounded to three decimal places.

5 0

3 years ago

e Carlos rented a truck for one day. There was a base fee of $ 20.99 , and there was an additional charge of 88 cents for each m

Sonja [21]

Let Base fee be X and No. of Miles be Y.

According to the question
Total Charge= (X+ 88Y)
251.55=20.99+ 0.88Y
Y= 251.55-20.99/0.88
Y= 262 miles

7 0

3 years ago

Read 2 more answers