The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
Read more about radius
brainly.com/question/13449316
#SPJ4
Answer:
the tire should be 16 inches in diameter
a way that you can find diameter is if you are given the radius and you just multiply that number by 2 or ADD the same number because usually it is half of the diameter
Answer:
AC = 25.5 or 1.5
Step-by-step explanation:
If they are on a line and they are in the order ABC
AB + BC = AC
12+13.5 = AC
25.5 = AC
If they are on a line and they are in the order CAB
CA + AB = BC
AC + 12 =13.5
AC = 13.5 -12
AC = 1.5
If they are on a line and they are in the order ACB
That would mean that AB is greater than BC and that is not the case
Answer:
12,157,665,459,057,000,000
Step-by-step explanation:
It seems like it would have to involve exponents. 3 to the 40th power would be 12,157,665,459,057,000,000.
