1) B 60 roses 10 carnations
2) D (3,-2),(-2,-6),(3,4)
Given:
baked: 6 <span>cookies and 4 brownies
can bake 25 more either </span><span>cookies or brownies
</span><span>Let x represent the number of more cookies that Midge can bake
Let y represent the number of more brownies that Midge can bake.
cookies = 6 + x
brownies = 4 + y
(6 + x) + (4 +y) </span>≤ 25
10 + x + y ≤ 25
x + y ≤ 25 - 10
x + y ≤<span> 15
y </span>≤ <span>15 - x
</span><span>The following graphs best represents the relationship between x and y is:
</span>
<span>line joining ordered pair 0, 15 and 7, 8 and the region below this line which lies in the first quadrant is shaded</span><span>
</span>
Answer: A.
.
Step-by-step explanation:
The given inequation: 

Multiplying 5 on both the sides, we get

Hence, the inequality for x is
.
So, the correct option is A.
..
Answer:
a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b)0.6004
c)19.607
Step-by-step explanation:
Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2
X ~ Poisson(A) where 
a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar

50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55
So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment
Let X denotes the number of grams to be eaten before another fragment is detected.

c)The expected number of grams to be eaten before encountering the first fragments :
s
It would be D because you need to multiply 38 and 50. But x is the length of one classroom, and because we don't know it, you would get 38(50-x).
Good luck!!