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laiz [17]
3 years ago
8

When Jeremy surveyed thirty 7th-grade students at the community pool, he found that 2/15 had not read at least one book during J

uly. He knows there are about 200 7th-grade students in his community, so he infers that about 40 of them did not read any books in July. Is that a good inference? Explain.
Mathematics
2 answers:
WITCHER [35]3 years ago
4 0

.....Jeremy did not make a good inference. The ratio is not in proportion to 2/15. The correct inference would be about 26 students who did not read any books in July. The sample might be biased since it was limited to those at the pool....

Valentin [98]3 years ago
3 0

Answer:

Jeremy did not make a good inference. The ratio is not in proportion to 2/15. The correct inference would be about 26 students who did not read any books in July. The sample is biased since it was limited to those at the pool

Step-by-step explanation:

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1) B 60 roses 10 carnations
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3 0
2 years ago
Midge baked 6 cookies and 4 brownies. Midge only has enough ingredients to bake at most 25 cookies or brownies total. Let x repr
GenaCL600 [577]
Given:
baked: 6 <span>cookies and 4 brownies
can bake 25 more either </span><span>cookies or brownies

</span><span>Let x represent the number of more cookies that Midge can bake
Let y represent the number of more brownies that Midge can bake.

cookies = 6 + x
brownies = 4 + y

(6 + x) + (4 +y) </span>≤ 25
10 + x + y ≤ 25
x + y ≤ 25 - 10
x + y ≤<span> 15

y </span>≤ <span>15 - x


</span><span>The following graphs best represents the relationship between x and y is:
</span>
<span>line joining ordered pair 0, 15 and 7, 8 and the region below this line which lies in the first quadrant is shaded</span><span>

</span>

4 0
3 years ago
Read 2 more answers
Pls guys help me pls :c​
Vinil7 [7]

Answer: A. x\geq21\dfrac{2}{3} .

Step-by-step explanation:

The given inequation: 81-1\dfrac{1}{5}x\leq55

\Rightarrow\ 81-\dfrac{6}{5}x\leq55

Multiplying 5 on both the sides, we get

5(81-\dfrac{6}{5}x)\leq5\times55\\\\\Rightarrow\ 405-6x\leq275\\\\\Rightarrow\ 6x\geq405-275\\\\\Rightarrow\ 6x\geq130\\\\\Rightarrow\ x\geq\dfrac{130}{6}\\\\\Rightarrow\ x\geq\dfrac{65}{3}\\\\\Rightarrow\ x\geq21\dfrac{2}{3}

Hence, the inequality for x is x\geq21\dfrac{2}{3} .

So, the correct option is A. x\geq21\dfrac{2}{3} ..

8 0
3 years ago
Suppose the number of insect fragments in a chocolate bar follows a Poisson process with the expected number of fragments in a 2
leonid [27]

Answer:

a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55

b)0.6004

c)19.607

Step-by-step explanation:

Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2

X ~ Poisson(A) where \lambda = \frac{10.2}{200} = 0.051

a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar

\frac{1}{4} \times 200 = 50

50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55

So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55

b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment

Let X denotes the number of grams to be eaten before another fragment is detected.

P(X>10)= e^{-\lambda \times x}= e^{-0.051 \times 10}= e^{-0.51}=0.6004

c)The expected number of grams to be eaten before encountering the first fragments :

E(X)=\frac{1}{\lambda}=\frac{1}{0.051}=19.607 grams

7 0
3 years ago
A large room has the dimensions shown below.A partition is to be installed so that 2 classes can use it.The area of the smaller
Artemon [7]

It would be D because you need to multiply 38 and 50. But x is the length of one classroom, and because we don't know it, you would get 38(50-x).

Good luck!!

8 0
3 years ago
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