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zzz [600]
2 years ago
11

2(-6x-4)+3 = 3(3x-3)+4

Mathematics
2 answers:
iren2701 [21]2 years ago
8 0

Answer:

x = 0

Step-by-step explanation:

For this problem, we will simply solve the equation by isolating the variable x, to find the value of x.

2(-6x - 4) + 3 = 3(3x - 3) + 4

2*(-6x) + 2*(-4) + 3 = 3*(3x) + 3*(-3) + 4

-12x + -8 + 3 = 9x + -9 + 4

-12x + -5 = 9x + -5

12x + -12x + -5 = 12x + 9x + -5

-5 = 21x + -5

5 + -5 = 21x + -5 + 5

0 = 21x

0 = x

Hence, in this equation, the value of x is 0.

Cheers.

forsale [732]2 years ago
7 0

Answer:

x = 0

Step-by-step explanation:

2(-6x-4)+3=3(3x-3)+4\\\\-12x-8+3=9x-9+4\\\\-12x-5=9x-5\\\\-12x-5+5=9x-5+5\\\\-12x=9x\\\\-12x-9x=9x-9x\\\\-21x=0\\\\\frac{-21x=0}{21}\\\\ \boxed{x=0}

Hope this helps.

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Answer:

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Step-by-step explanation:

<u>Equation of a Circle</u>

A circle of radius r and centered on the point (h,k) can be expressed by the equation

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We are given the equation of a circle as

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Note we have corrected it by adding the square to the y. Simplify by 3

x^2+y^2-2\alpha x+4y-\alpha=0

Complete squares and rearrange:

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We can see that, if r=4, then

\alpha+\alpha^2+4=16

Or, equivalently

\alpha^2+\alpha-12=0

There are two solutions for \alpha:

\alpha=-4,\ \alpha=3

Keeping the positive solution, as required:

\boxed{\alpha=3}

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