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valentinak56 [21]
3 years ago
12

A sign 4 meters tall cast a shadow 5 meters long . At the same time, a tree casts a shadow 30 meters long. What is the height of

the tree?
Mathematics
1 answer:
AfilCa [17]3 years ago
5 0
The information's given in the question are of vital importance. These information's should be very useful while getting to the desired answer of the given question.Let us now concentrate on the problem that needs to be solved.
The height of the sign that casts a shadow of 4 meters is = 5 meters
Then
The height of the tree that casts a shadow of 30 meters = (5/4) * 30 meters
                                                                                          = 150/4 meters
                                                                                          = 37.5 meters
So the tree casting a shadow of 30 meters is actually 37.5 meters in height. I hope the procedure is simple enough for you to understand.
You might be interested in
The Burj Khalifa, a building in Dubai, United Arab Emirates, is about 828 meters tall. Brody is making a scale model of this bui
Sonja [21]
The correct answer for this question is this one: "Roughly 1.7 meters."

The height is 828 meters tall. The scale model is 1 meter is equal to 500 meters.

To the nearest tenth, Brody's model of the Burj Khalifa should be
= 828 / 500
= 1.656 meter
Roughly 1.7 meters.


Hope this helps answer your question and have a nice day ahead.
3 0
2 years ago
Im almost done with it
baherus [9]

Answer:

Area of rectangle = \mathbf{x^2-4x}

Perimeter of rectangle = \mathbf{4x-8}

Step-by-step explanation:

We are given:

Length of rectangle = x

Width of rectangle = x-4

We are not given if we want to find area of rectangle or perimeter of rectangle.

So, I will be finding both

Area of rectangle

The formula used is: Area\: of\: rectangle=Length \times Width

Putting values and finding area

Area\: of\: rectangle=Length \times Width\\Area\: of\: rectangle=x \times (x-4)\\Area\: of\: rectangle=x^2-4x

So, we get area of rectangle = \mathbf{x^2-4x}

Perimeter of rectangle

The formula used is: Perimeter \: of\: rectangle=2(Length+ Width)

Putting values and finding perimeter

Perimeter \: of\: rectangle=2(Length+ Width)\\Perimeter \: of\: rectangle=2(x+ x-4)\\Perimeter \: of\: rectangle=2(2x-4)\\Perimeter \: of\: rectangle=4x-8

So, we get perimeter of rectangle = \mathbf{4x-8}

I hope, it can help in solving the question.

4 0
2 years ago
Please make it correct..I need to pass this...
Sergio [31]
Simplify them all down to 5 then solve
6 0
2 years ago
Read 2 more answers
Find the values of x and y.
Ipatiy [6.2K]
Value of X and Y is 90 and 26 respectively.
3 0
3 years ago
Given:Bc biscects ABD mAbd=52° prove: mABC =26°<br>​
vovikov84 [41]

Answer:

Angle Bisector Theorem

Step-by-step explanation:

7 0
3 years ago
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