The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
They each would pay 2.55
12.75 divided by 5 = 2.55
Answer: b is the answer
Step-by-step explanation:
Width = w
Length = 5w
Given,
Perimeter = 276 ft
5w * w = 276
w² = 55.2
--- w = 7.429670248402684 ≈ 7.43 ft
--- l = 5w = 5*7.43 = <span>37.14835124201342 </span>≈ 37.15 ft
Answer:
n + 14
I don't know if it's correct but i'm trying to help :)