As anoutline, angles O and Q are inscribed angles which are measured by one-half of its intercepted arc.
angle O = 1/2 arc RQP
angle Q = 1/2 arc ROP
so arcs RQP and ROP together make up the entire circle which has 360 degrees.
so angles O and Q is 1/2 (360) = 180 degrees (supplementary angles).
The formula for distance is equal to:
d = v * t
where d is distance, v is velocity or speed, and t is
time
Since the distance travelled by the two airplane is
similar, therefore we can create the initial equation:
v1 * t1 = v2 * t2
We know that v1 = 496, and v2 = 558 so:
496 t1 = 558 t2
or
x = 558 t2 / 496
We also know that airplane 1 travelled 30 minutes (0.5
hours) earlier than airplane 2, therefore:
x = t2 + 0.5
Hence,
496 (t2 + 0.5) = 558 t2
496 t2 + 248 = 558 t2
t2 = 4 hours
x = t2 + 0.5 = 4 + 0.5
x = 4.5 hours
So the equation is:
x = 558 t2 / 496
And the first plane travelled:
x = 4.5 hours
Answer:
$20,720
Step-by-step explanation:
$518,000 x 4% = $20,720
