Answer:
a
Since the integral has an infinite discontinuity, it is a Type 2 improper integral
b
Since the integral has an infinite interval of integration, it is a Type 1 improper integral
c
Since the integral has an infinite interval of integration, it is a Type 1 improper integral
d
Since the integral has an infinite discontinuity, it is a Type 2 improper integral
Step-by-step explanation:
Considering a

Looking at this we that at x = 3 this integral will be infinitely discontinuous
Considering b

Looking at this integral we see that the interval is between
which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral
Considering c

Looking at this integral we see that the interval is between
which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral
Considering d

Looking at the integral we see that at x = 0 cot (0) will be infinity hence the integral has an infinite discontinuity , so it is a Type 2 improper integral
1. First find the LCD of the two fractions.
They share the denominator 6.
Turn 1/2 into a fraction with a denominator of 6.
2*3=6, so 1*3=3
3/6
Now add.
Leave denominators alone, but add numerators.
3+5=8
8/6
Now simplify.
Divide both by 2.
8/2=4
6/2=3
4/3 is your answer or 1 1/3
2. Multiply straight across.
3*2=6
4*7=28
6/28
Simplify
You get 3/14 as your answer.
Remember that the slope of a line never changes, so you can choose whatever 2 points you want and you will always get the same slope. Calculate the rise and run (You can draw it on the graph if it helps). The slope is 2/4, which , of course, you can simplify to ½.
1 more than 9 is 10.
That is because 10-9 = 1.
Answer:
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