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Zigmanuir [339]
3 years ago
13

Find the midpoint of segment EF if E (5,-2) F(1,-8) URGENT

Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0

Answer

(3, -5)

Step-by-step explanation:

hope it helps :)

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Help this is due today​
bearhunter [10]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
What are the zeros of 3x^2+5x-12
levacccp [35]

Factor the quadratic equation (3x-4)(x+3). Then set the factors equal to zero.

3x-4=0, solve to get 4/3

x+3=0 x=-3

5 0
3 years ago
In the figure below, R=2 cm, Q= 2cm, and P= 3 cm. The figure of a small rectangle, a large rectangle, and one-fourth of a circle
VLD [36.1K]

Answer: The perimeter is 10.1415925, which you can round down to 10, or leave it as is.

8 0
3 years ago
A software engineer is creating a new computer software program. She wants to make sure that the crash rate is extremely low so
Soloha48 [4]

Answer:

a) the sample size is 400

b) 95% confidence Interval for p is ( 0.0286, 0.0714 )

Step-by-step explanation:

Given the data in the question;

sample size n = 400

x = 20

p = x / n = 20 / 400 = 0.05

q = 1 - p = 1 - 0.05 = 0.95

a)

n = 400

Hence, the sample size is 400

b) 95% confidence Interval for p;

At 95% confidence interval,

significance level ∝ = 1 - 95% = 1 - 0.95 = 0.05

∝/2 = 0.05 / 2 = 0.025

so, Z critical Value ; Z_{\alpha /2 = 1.96  { from table }

So for Confidence Interval for p;

⇒ p' ± Z_{\alpha /2√( p'q' / n )

we substitute

⇒ 0.05 ± 1.96√( (0.05 × 0.95 ) / 400 )

⇒ 0.05 ± 1.96√( 0.00011875 )

⇒ 0.05 ± 1.96 × 0.010897

⇒ 0.05 ± 0.021358

⇒ ( 0.05 - 0.021358 ), ( 0.05 + 0.021358 )

⇒ ( 0.0286, 0.0714 )

Therefore, 95% confidence Interval for p is ( 0.0286, 0.0714 )

8 0
2 years ago
Which graph represents an odd function?
Nookie1986 [14]

Answer:

<h2>The first graph in the second image is an odd function.</h2>

Step-by-step explanation:

An odd function has a graph that it's symmetric about the origin, that is, the origin is like a mirror. In other words, the graph of an odd function has a specific symmetry about the origin.

So, we have to look for those graph that has symmetrical points in opposite quadrants, I and III or II and IV.

You can observe that the first graph of the second image has this behaviour. You can see that the points are symmetrical across the origin. If you graph a line defined as y=-x, you will observe that such line acts like a mirror.

Therefore, the odd function is the first graph in the second image.

8 0
3 years ago
Read 2 more answers
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