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Zigmanuir [339]
3 years ago
13

Find the midpoint of segment EF if E (5,-2) F(1,-8) URGENT

Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0

Answer

(3, -5)

Step-by-step explanation:

hope it helps :)

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Suppose you just purchased a digital music player and have put 9 tracks on it. After listening to them you decide that you like
ioda

a) consider the first song played . The probability of its being liked is 4/9.

And for second song, we have 3 liked songs and 8 remaining songs.

Hence probability of second being liked is 3/8.

Overall probability = (4/9)*(3/8) = 1/6 = 0.167 hence it is almost unusual.

b) First song being not liked is 5/9.

And for second song being not liked is 4/8.

Hence overall probability = (5/9)*(4/8) = 5/18.

c) To like exactly one of them, it has 2 possibilities. First song may be liked and second song disliked = (4/9)*(5/8) = (5/18)

First song may be disliked and second song liked = (5/9)*(4/8) = (5/18)

Hence overall probability = (5/18)+(5/18) = 5/9

d)  a)Probability of 2 songs liked by me with replacement means in both cases i have to select a song from 4 liked songs.

Hence probability = (4/9)*(4/9) = 16/81

b) probability of both being not liked by me is = (5/9)*(5/9) = (25/81)

c) probability of exactly one being liked = (4/9)*(5/9)+(5/9)*(4/9) = 40/81

8 0
3 years ago
-78 = 5r +3 (5r - 6)
Ksju [112]

I think it might be r= -3

5 0
3 years ago
Read 2 more answers
Use the drawing tools to form the correct answer on the number line.
Ainat [17]

Answer:

In the picture

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Which interval is the solution set to 0.35x - 4.8<5.2- 0.9x
stiks02 [169]

Answer:

Solution set {x|x<8}

Step-by-step explanation:

0.35x - 4.8<5.2- 0.9x

0.35x+0.9x<5.2+4.8

1.25x<10

x<10/1.25

x<8

Solution set {x|x<8}

4 0
3 years ago
Read 2 more answers
What is the correct answer?
egoroff_w [7]
X⁴ - 81  = x⁴ - 9² (Difference of 2 squares, then we an write it:


(x²-3)(x²+3) =0, → then (x²-3) = 0 and (x²+3)=0

(x²-3) = 0 → x² = 3 → x = +√3 and x = -√3
(x²+3) =0 → x² = -3 → x = +√-3  and x = -√3→ or  i√3 AND  x = -i√3

A{ -3 , +3 , -i√3 , i√3}

4 0
3 years ago
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