Help me solv[tex]tanx=1/2, \pi \ \textless \ x\ \textless \ 3 \pi /2

Mathematics

1 answer:

Softa [21]3 years ago

5 0

I don't know sorry I tried

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Adjoint of [1 0 2 -1] is

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The adjoint of the matrix $\left[\begin{array}{cc}1&0\\2&-1\end{array}\right]$ is $\left[\begin{array}{cc}-1&0\\-2&1\end{array}\right]$

<h3>How to determine the adjoint?</h3>

The matrix is given as:

$\left[\begin{array}{cc}1&0\\2&-1\end{array}\right]$

For a matrix A be represented as:

$A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right]$

The adjoint is:

$Adj = \left[\begin{array}{cc}d&-b\\-c&a\end{array}\right]$

Using the above format, we have:

$Adj = \left[\begin{array}{cc}-1&0\\-2&1\end{array}\right]$

Hence, the adjoint of the matrix $\left[\begin{array}{cc}1&0\\2&-1\end{array}\right]$ is $\left[\begin{array}{cc}-1&0\\-2&1\end{array}\right]$