Question

What is the equation of a circle with the center (4,-3) and a radius of 3

Answer 1

The equation of a circle with the center (4,-3) and a radius of 3 is:

(x-4)^2+(y+3)^2=9

Step-by-step explanation:

Given

Radius = r = 3

Centre = (h,k) = (4,-3)

The general form of equation of circle is:

$(x-h)^2+(y-k)^2=r^2$

Putting the values of center and radius

$(x-4)^2+[y-(-3)]^2=(3)^2\\(x-4)^2+(y+3)^2=9$

Hence,

The equation of a circle with the center (4,-3) and a radius of 3 is:

(x-4)^2+(y+3)^2=9

Keywords: circle, Equation of circle

Learn more about equation of circle at:

• brainly.com/question/3950386
• brainly.com/question/4021035

#LearnwithBrainly