Part 1
Let:
y be the total cost
x be the number of tickets
a be fair admission
Since the fair charges $1.25 per ticket, the equation of the line would look like:
y = 1.25x + a
Since Johnny spent $43.75 and bought 25 tickets, we find a by replacing y with 43.75 and x with 25:
43.75 = 1.25×25 + a
Now solve for a
43.75 = 31.25 + a
43.75 - 31.25 = a
a = 12.50
Going back to the first equation:
y = 1.25x + 12.50
Part 2:
a) Let (9,8) be (x1,y1) and (4,-12) be (x2,y2)
The formula for slope is:

b) For the point-slope equation, I'll use (9,8)
Using the formula:

c) For the slope-intercept form, we solve for y in the point-slope formula:
Answer:
1.16
Step-by-step explanation:
Given that;
For some positive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770.
This implies that:
P(0<Z<z) = 0.3770
P(Z < z)-P(Z < 0) = 0.3770
P(Z < z) = 0.3770 + P(Z < 0)
From the standard normal tables , P(Z < 0) =0.5
P(Z < z) = 0.3770 + 0.5
P(Z < z) = 0.877
SO to determine the value of z for which it is equal to 0.877, we look at the
table of standard normal distribution and locate the probability value of 0.8770. we advance to the left until the first column is reached, we see that the value was 1.1. similarly, we did the same in the upward direction until the top row is reached, the value was 0.06. The intersection of the row and column values gives the area to the two tail of z. (i.e 1.1 + 0.06 =1.16)
therefore, P(Z ≤ 1.16 ) = 0.877
FAFSA -- free application for federal student aid.....so answer would be student specific financial aid
Answer:
she spent 75%
Step-by-step explanation: