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REY [17]
3 years ago
13

The graph below shows a proportional relationship between y and x. What is the constant of proportionality, y/x?

Mathematics
2 answers:
steposvetlana [31]3 years ago
7 0

Answer:

1,40

Step-by-step explanation:

aliya0001 [1]3 years ago
4 0

Answer:

<h2>3.5</h2>

Step-by-step explanation:

We can find the constant of proportionality by finding the value of y when x = 1.

y = 3.5 when x = 1

The constant of proportionality, y/x, is 3.5/1 or just 3.5.

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Which list shows the in greatest to least?<br><br>(NEED ASAP)
NeX [460]

The answer is B.

\frac{14}{5} = \frac{28}{10}

\frac{5}{2} = \frac{25}{10}

1\frac{3}{10} = \frac{13}{10}

\frac{3}{5} = \frac{6}{10}

If you find a common denominator, the process becomes much easier. I hope this was helpful.

8 0
3 years ago
Terrence finished a word search in 3/4 the time it took frank. charlotte finished the word search in 2/3 the time it took terren
Luden [163]

Answer:

Charlotte-16

Step-by-step explanation:

In order to calculate the time that Charlotte took we just first have to calculate the time that Terrence took to finish the word search, that is done by multiplying the 32 minutes that Frank took by the three quartes that it took terrence:

Time=(\frac{3}{4}) (32)\\Time=(\frac{96}{4})\\Time=24

So now we know that It took terrence 24 minutes, and that Charlotte took two thirds of that time so we now just multiply that:

Time=(\frac{2}{3}) (24)\\Time=(\frac{48}{3})\\Time=16

6 0
3 years ago
Read 2 more answers
Find the surface area of a cone if the diameter of its base is 13.5 feet, and it has a slant height of 16.8 feet. Round to the n
Tresset [83]

The diameter is given which is 13.5feet and radius is half of diameter. Therefore radius = 6.75 feet.

Slant height = 16.8 feet

The formula of surface area of cone is

S = \pi *r(r+l) \\ S = \pi*6.75(6.75+16.8) \\ S =\pi*6.75*23.55 = 499.2 ft^2

Correct option is C

5 0
3 years ago
Answers for adding and subtracting polynomials
lakkis [162]
Please explain more :))

Oh nvm this
(4+9) + (2-1) = 12
5 0
3 years ago
Enter the values of h and I so that y=x2+6x+10 is in vertex form<br> Y=(x+__)^2+___
DiKsa [7]

Use\ (a+b)^2=a^2+2ab+b^2\qquad(*)\\\\y=x^2+6x+10=x^2+2(x)(3)+10=\underbrace{x^2+2(x)(3)+3^2}_{(*)}-3^2+10\\\\=(x+3)^2-9+10=(x+3)^2+1\\\\Answer:\ \boxed{y=(x+3)^2+1}

3 0
3 years ago
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