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3 years ago

A frction with fractions in either the numerator or the denominator or both called a??

Mathematics

1 answer:

makkiz [27]3 years ago

8 0

Answer:

compound fraction

Step-by-step explanation:

When a “normal” fraction contains fractions in either the numerator or denominator or both, then we consider it to be a complex fraction. This type of fraction is also known as a compound fraction. There are two methods used to simplify such kind of fraction.

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Find the leg of each isosceles right triangle if hypotenuse is 5 square root 6

Mekhanik [1.2K]

Let x be the measure of both legs since the given is an isosceles right triangle. By the Pythagorean theorem we calculate for the legs,
x² + x² = (5 sqrt 6)²
The value of x from the given equation is approximately 8.66 units.

7 0

3 years ago

Use the distance formula to find the perimeter. Round to the nearest tenth.

weeeeeb [17]

Answer:

12.5

Step-by-step explanation:

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3 years ago

Is 3.50s+5.00L less than or equal to 80 a system of linear inequalities

kirill [66]

Answer:

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i hope this helps

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3 years ago

What is the sum of the first 51 consecutive odd positive integers?

Angelina_Jolie [31]

We call:

$a_{n}$ as the set of the first 51 consecutive odd positive integers, so:

 $a_{n} = \{1, 3, 5, 7, 9...\}$

Where:
$a_{1} = 1$
$a_{2} = 3$
$a_{3} = 5$
$a_{4} = 7$
$a_{5} = 9$
and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

 $a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}$

Then:

 $a_{n} = a_{1} + (n-1)d$

So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

 $S_{k} = ( \frac{a_{1} + a_{k}}{2} ).k$

Therefore, we need to find:
 $a_{k} = a_{51}$

Given that $a_{1} = 1$ , then:

$a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1$

Thus:
$a_{k} = a_{51} = 2(51)-1 = 101$

Lastly:

$S_{51} = ( \frac{1 + 101}{2} ).51 = 2601$

4 0

4 years ago

B = 18, c = 30 a = ?

Mekhanik [1.2K]

A is 6 can I have brainliest

4 0

3 years ago