Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
Answer = a
Explanation- A cube is a 3D figure and each face would be a square since it is a cube. Since each side is a square all the sides are the same Width, Length, and height. Therefor you would be multiplying whatever number your have by itself 3 times because the formula would be Length x Width x Height
Answer:
I am going to say x3
Step-by-step explanation:
9514 1404 393
Answer:
1 mile
Step-by-step explanation:
5 × (1/5 mi) = 5/5 mi = 1 mi
The students ran 1 mile in all.
The price dropped by forty two dollars. We can work this out by simply
multiplying six, the number that we know the jeans were reduced by each
week, by seven, the number of weeks that the jeans continued to reduce
in price for. Six times seven is of course forty two.
