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Assoli18 [71]
3 years ago
12

If you apply the changes below to the quadratic parent function, f(x)=x^2 which of these is the equation of the new function?

Mathematics
1 answer:
g100num [7]3 years ago
5 0

Answer:

A

Step-by-step explanation:

Given the parent function y = x², then

y = (x + a) represents a horizontal translation

• If a > 0 , then shift to the left of a units

• If a < 0, then shift to the right of a units

Thus a shift of 3 units left ⇒ y = (x + 3)²

------------------------------------------------------------

A vertical stretch of a units, stretches away from the x- axis

A vertical compression of a units, compresses towards the x- axis

• | a | > 1 is a stretch

• 0 < | a | < 1 is a compression

Thus a vertical stretch of 4 ⇒ y = 4(x + 3)²

--------------------------------------------------------------

A reflection in the x- axis, negates the y- coordinate

y = - 4(x + 3)² → A

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Nina can type 124 words in 4 minutes.at this rate how many words can nina type in an hour
Ludmilka [50]

Answer:

<em>1,860</em>

Step-by-step explanation:

FIRST:

we divide 124 by 4 because in 4 minutes he can type 124 words, and we need to figure out how many he can type in a minute.

124 divided by 4 is 31. (they can type 31 wpm)

NEXT: now we know they can type 31 wpm, we need to multiply that number by 60 because there are 60 minutes in an hour.

31 x 60 = 1,860

therefore, they can type 1860 words per hour

hope i helped have a great day/night! :'')

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Answer:

3/24 or .125%

Step-by-step explanation:

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2 years ago
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3 years ago
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Use the Ratio Test to determine whether the series is convergent or divergent.
natka813 [3]

Answer:

The series is absolutely convergent.

Step-by-step explanation:

By ratio test, we find the limit as n approaches infinity of

|[a_(n+1)]/a_n|

a_n = (-1)^(n - 1).(3^n)/(2^n.n^3)

a_(n+1) = (-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)

[a_(n+1)]/a_n = [(-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)] × [(2^n.n^3)/(-1)^(n - 1).(3^n)]

= |-3n³/2(n+1)³|

= 3n³/2(n+1)³

= (3/2)[1/(1 + 1/n)³]

Now, we take the limit of (3/2)[1/(1 + 1/n)³] as n approaches infinity

= (3/2)limit of [1/(1 + 1/n)³] as n approaches infinity

= 3/2 × 1

= 3/2

The series is therefore, absolutely convergent, and the limit is 3/2

3 0
3 years ago
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