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iVinArrow [24]
3 years ago
11

What are the zeros of f(x) = x2 - 12x + 36?

Mathematics
1 answer:
Otrada [13]3 years ago
4 0

Answer:

A X=6 only

Step-by-step explanation:

{x}^{2} - 12x + 36  = 0\\ x {}^{2}  - 6x - 6x + 36 = 0 \\ x(x - 6) - 6(x - 6) = 0 \\ (x - 6)(x - 6) = 0 \\ x - 6 = 0 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: x - 6 = 0 \\ x = 6 \:  \:  \:  \: or \:  \:  \:  \:  \:  x = 6

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