Answer:
{-infinity, infinity}
no solution
Step-by-step explanation:
|x| +15≥4
Subtract 15 from each side
|x| +15-15≥4-15
|x| ≥-11
This is always true so x can be and real number
{-infinity, infinity}
-2|5x+3| = 8
Divide by -2
-2/-2|5x+3| = 8/-2
|5x+3| = -4
This can never happen because absolute values are zero or greater
no solution
Https://us-static.z-dn.net/files/d8d/e008ced388704d59896d3bf37158f465.jpeg
Answer:
5
Step-by-step explanation:
you need to look at how far it is from a m=number line to find the absolute value
Answer:
1.) Yes
2.) Yes
Step-by-step explanation:
Given that
n = k(k + 7)
If k is a positive integer and n = k(k + 7), is n divisible by 6 ?
(1) k is odd. Yes.
Let assume that k = 3
Then, n = 3(3 + 7)
n = 3 × 10
n = 30.
30 is divisible by 6.
(2) When k is divided by 3, the remainder is 2. That is,
Let k = 5
Then,
5/3 = 1 remainder 2
Substitute k into the equation
n = k(k + 7)
n = 5(5 + 7)
n = 5 × 12
n = 60
And 60 is divisible by 6.
Therefore, the answer to both questions is Yes.
