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Gnesinka [82]
4 years ago
5

Complete the recursive formula of the geometric sequence 16\,,\,3.2\,,\,0.64\,,\,0.128,...16,3.2,0.64,0.128,

Mathematics
1 answer:
Nastasia [14]4 years ago
3 0

Answer:

a_{n+1}=0.2a_n for all n>0, a_1=16

Step-by-step explanation:

Let \{a_n\}=\{16,3.2,0.64,0.128,\cdots \} be the sequence described.

A geometric sequence has the following property: there exists some r (the ratio of the sequence) such that \frac{a_{n+1}}{a_n}=r forr all n>0.

To find r, note that

\frac{3.2}{16}=\frac{32}{10(16)}=\frac{2}{10}=\frac{1}{5}=0.2

Similarly

\frac{0.64}{3.2}=\frac{64}{10(32)}=\frac{1}{5}=0.2

\frac{0.128}{0.64}=\frac{1}{5}=0.2

Thus a_{n+1}=r a_n=\frac{a_n}{5}=0.2a_n for all n>0, and a_1=16

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Answer: a) √50

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Step-by-step explanation:

first, the modulus of a complex number z = a + bi is

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The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:

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n = a  + bi

Im + nI = 3√10

Im + n I = √(a^2 + b^2 + 2^2 + 6^2)= 3√10

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             a^2 + b^2 + 40 = 3^2*10 = 9*10 = 90

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The modulus of n must be equal to the square root of 50.

now we can find any values a and b such a^2 + b^2 = 50.

for example, a = 1 and b = 7

1^2 + 7^2 = 1 + 49  = 50

Then a possible value for n is:

n = 1 + 7i

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