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jekas [21]
3 years ago
8

25PTS!!

Mathematics
2 answers:
dimaraw [331]3 years ago
8 0

Answer:

The recursive formula is given as:

a_n = 3a_{n-1}+2 , n is the number of terms

where,

a_4 = 20

We have to find  first three terms of the sequence.

For n =4 ;

a_4 = 3a_{4-1}+2

⇒a_4 = 3a_3+2

⇒20 = 3a_3+2

Subtract 2 from both sides we have;

18= 3a_3

Divide both sides by 3 we have;

6 = a_3

or

a_3 =6

For n = 3;

a_ 3= 3a_{2}+2

⇒6 = 3a_2+2

Subtract 2 from both sides we have;

4= 3a_2

Divide both sides by 3 we have;

a_2 = \frac{4}{3}

For n =2

a_2= 3a_{1}+2

⇒\frac{4}{3} =3a_1+2

Subtract 2 from both sides we have;

-\frac{2}{3}= 3a_3

Divide both sides by 3 we have;

a_1 =-\frac{2}{9}

Therefore, the first three terms of the sequence  are:

a_1 =-\frac{2}{9}

a_2 = \frac{4}{3}

a_3 =6

AveGali [126]3 years ago
5 0
The answer is
a1 =-2/9
a2 =4/3
a3 =6
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