For this case, the first thing to do is write the equation of moving the ball. We have then: h (t) = - 16t ^ 2 + 130t + 2 Deriving we have: h '(t) = - 32t + 130 We match zero: -32t + 130 = 0 We cleared t: t = 130/32 t = 4.0625 s We evaluate the value of t = 4.0625 s in the equation of motion: h (4.0625) = - 16 * (4.0625) ^ 2 + 130 * (4.0625) + 2 h (4.0625) = 266.0625 feet Answer: The maximum height, in feet, the ball will attain is: h (4.0625) = 266.0625 feet
