Ok so, we have the fact that 1.20 per mile Lets represent m as each additional mile so we have 1.20m which is That much per additional mile So For the first 5 functions we have f(1) = 20 f(2) = 20 f(3) = 20 f(4) = 20 f(5) = 20 Only for the first 5 miles though, since it is a flat fee. So for the additional miles we go back to what I said in the first Paragraph. 1.20m That is for additional miles, so that will be added to 20 So if you travel more than 5 miles the function looks like this: f(x) = 20 + 1.20m So the first 5 miles it is: f(x) = 20 For 7 mles the function would look like: f(7) = 20 + 1.20(2) It is a 2 because it is the additional mile, which is 2 hope this helps

7 0

3 years ago

With bases V1, V2 , V3 andw1, w2 , W3, suppose T(v1) = w2 and T(v2) = T(v3) = w1 + w3 . T is a linear transformation. Find the m

Roman55 [17]

Answer:

See picture and explanation below.

Step-by-step explanation:

With this information, the matrix A that you can find is the transformation matrix of T. The matrix A is useful because T(x)=Av for all v in the domain of T.

A is defined as $T=([T(v_1)] [T(v_2] [T(v_3)])\text{ where }[T(v_i)]$ denotes the vector of coordinates of $T(v_i)$ respect to the basis (we can apply this definition because forms a basis for the domain of T).

The vector of coordinates can be computed in the following way: if $T(v_i)=a_1w_1+a_2w_2+a_3w_3$ then $[T(v_i)]=(a_1,a_2,a_3)^t$ .

Note that we have all the required information: $T(v_1)=0w_1+1\cdot w_2+0w_3$ then $[T(v_1)]=(0,1,0)^t$

$T(v_2)=T(v_3)=1\cdot w_1+0w_2+0w_3$ hence $[T(v_2)]=[T(v_3)]=(1,0,0)^t$

The matrix A is on the picture attached, with the multiplication A(1,1,1).

Finally, to obtain the output required at the end, use the properties of a linear transformation and the outputs given:

$T(v_1+v_2+v_3)=T(v_1)+T(v_2)+T(v_3)=w_2+w_1+w_1=w_2+2w_1$

In this last case, we can either use the linearity of T or multiply by A.

4 0

3 years ago

Monica made a drawing of her patio using the scale 1 inch equals 4 feet. The length of the patio in her drawing was 11 inches. W

kow [346]

1 inch = 4 feet

11 inches = 44 feet (multiply both sides by 11)

<h3>Answer: 44 feet</h3>

6 0

3 years ago

I need help I’m bad at math

Alina [70]

If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].

The width of each rect. is 1/2.

The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.

The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:

{1.875, 2.5, 2.875}

Add these three areas together; you sum will represent the approx. area under the given curve on the given interval: 1.875+2.5+2.875 = ?

5 0

3 years ago