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3 years ago

True or false the product of a mixed number between four and five and affection between zero and one is always less than four

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

7 0

That answer is true

Sever21 [200]3 years ago

5 0

True I think so :) !!!!!

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Two motorcyclist A and B, started simultaneously moving towards each other. From the graph given below, find the distance each o

otez555 [7]

Answer:

Distance Covered by Motorcyclist A = 400 kilometers

Distance Covered by Motorcyclist B = 300 Kilometers

Time before they met = 5 hours

Average Speed of Motorcycle A = 80 kilometers per hour

Average Speed of Motorcycle B = 60 kilometers per hour

Step-by-step explanation:

At point t = 5 and d = 300 is their <em>meeting point</em>.

Distance Covered by Motorcyclist A = from 700 to 300 (meeting point), that is 700 - 300 = 400 kilometers

Distance Covered by Motorcyclist B = from 0 to 300 (meeting point), that is 300 - 0 = 300 kilometers

The time before they met went for 5 hours as shown in graph.

Average speed of each motorcycle is given by the slope of the line. We can figure this out easily. We have to find distance traveled per hour.

Average Speed of Motorcycle A = it went 400 km in 5 hours, so 400/5 = 80 kilometers per hour

Average Speed of Motorcycle B = it went 300 km in 5 hours, so 300/5 = 60 kilometers per hour

4 0

2 years ago

Find the greatest common factor of the monomial 46x^5 10x^3

Whitepunk [10]

2x^3

2 can fit into 10 and 46
and you can take 3 out of 3 and 5

3 0

2 years ago

1/3(m-1)=-5<br> Please help

dezoksy [38]

Answer:

m=-14 I hope this helps u

Step-by-step explanation:

6 0

3 years ago

Find the distance traveled by a particle with position (x, y) as t varies in the given time interval. x = 5 sin2 t, y = 5 cos2 t

rodikova [14]

$\begin{cases}x(t)=5\sin2t\\y(t)=5\cos2t\end{cases}\implies\begin{cases}\frac{\mathrm dx}{\mathrm dt}=10\cos2t\\\frac{\mathrm dy}{\mathrm dt}=-10\sin2t\end{cases}$

The distance traveled by the particle is given by the definite integral

$\displaystyle\int_C\mathrm dS=\int_0^{3\pi}\sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2}\,\mathrm dt$

where $C$ is the path of the particle. The distance is then

$\displaystyle\int_0^{3\pi}\sqrt{100\cos^22t+100\sin^22t}\,\mathrm dt=10\int_0^{3\pi}\mathrm dt=30\pi$

6 0

3 years ago

Ayo help me please I give u 10 points

slavikrds [6]

Answer:

A and D

Step-by-step explanation:

Moving the line left would be moving it onto the y - axis

Therefore the solution would be any point that starts with 0

So (0, 1), (0, 2), (0, -9), etc.

3 0

2 years ago