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3 years ago

In what order are the following components used to create hydroelectric power?

Chemistry

2 answers:

RoseWind [281]3 years ago

7 0

Answer:The correct answer is option 2.

Explanation:

1. The water from the reservoir enter the pen-stock which guides the water towards the turbines.

2. The the water flowing down rotates the turbine which is further connected to generator in which electricity is generated.

3. The electricity generated by the generator is routed to wards the transformer which further distributes the electricity in different electrical lines.

The order of generations of hydroelectricity from the water is:

Reservoir→Penstock→Turbine-→Generator-→Transformer-→Electrical lines

Sindrei [870]3 years ago

6 0

The answer to this question is most- likely option 2

Hope I helped

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How many grams of sodium chloride are present in a 0.75 M solution with a volume of 500.0 mililiters

Ilya [14]

C = 0,75 mol/dm³
V = 500mL = 500cm³ = 0,5dm³

C = n/V
n = 0,75×0,5dm³
n = 0,375 moles

M NaCl: 23+35,5 = 58,5g

1 mole ---------- 58,5g
0,375 ----------- X
X = 0,375×58,5
X = 21,9375g NaCl

:)

5 0

4 years ago

Nitrogen dioxide is used industrially to produce nitric acid, but it contributes to acid rain and photochemical smog. What volum

Strike441 [17]

Answer:

35.41 L

Explanation:

Given, Volume of Copper = 4.84 cm³

Density = 8.95 g/cm³

Considering the expression for density as:

$Density=\frac {Mass}{Volume}$

So,

So, Mass= Density Volume = 8.95 g/cm³ 4.84 cm³ = 43.318 g

Mass of copper = 43.318 g

Molar mass of copper = 63.546 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{43.318\ g}{63.546\ g/mol}$

Moles of copper = 0.6817 moles

Given, Volume of nitric acid solution = 227 mL = 227 cm³

Density = 1.42 g/cm³

Considering the expression for density as:

$Density=\frac {Mass}{Volume}$

So,

So, Mass= Density Volume = 1.42 g/cm³ 227 cm³ = 322.34 g

Also, Nitric acid is 68.0 % by mass. So,

Mass of nitric acid = $\frac {68}{100}\times 322.34\ g$ = 219.1912 g

Molar mass of nitric acid = 63.01 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{219.1912\ g}{63.01\ g/mol}$

Moles of nitric acid = 3.4786 moles

According to the reaction,

$Cu_{(s)}+4HNO_3_{(aq)}\rightarrow Cu(NO_3)_2_{(aq)} + 2NO_2_{(g)} + 2H_2O_{(l)}$

1 mole of copper react with 4 moles of nitric acid

Thus,

0.6817 moles of copper react with 4*0.6817 moles of nitric acid

Moles of nitric acid required = 2.7268 moles

Available moles of nitric acid = 3.4786 moles

Limiting reagent is the one which is present in small amount. Thus, nitric acid is present in large amount, copper is the limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of copper on reaction forms 2 moles of nitrogen dioxide

So,

0.6817 mole of copper on reaction forms 2*0.6817 moles of nitrogen dioxide

Moles of nitrogen dioxide = 1.3634 moles

Given:

Pressure = 724 torr

The conversion of P(torr) to P(atm) is shown below:

$P(torr)=\frac {1}{760}\times P(atm)$

So,

Pressure = 724 / 760 atm = 0.9526 atm

Temperature = 28.2 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (28.2 + 273.15) K = 301.35 K

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9526 atm × V = 1.3634 mol × 0.0821 L.atm/K.mol × 301.35 K

⇒V = 35.41 L

3 0

3 years ago

What is the concentration of a solution?

Ludmilka [50]

Concentration Definition. In chemistry, concentration refers to the amount of a substance per defined space. Another definition is that concentration is the ratio of solute in a solution to either solvent or total solution. Concentration usually is expressed in terms of mass per unit volume.

Concentration = no of moles of solute/solvent

5 0

4 years ago

A 49.3 sample of CaCO3 was treated with aqueous H2SO4, producing calcium sulfate, 3.65 g of water and CO2(g). What was the % yie

yaroslaw [1]

Answer:

41.1%

Explanation:

First write the balanced reaction:

CaCO₃ + H₂SO₄ → CaSO₄ + H₂O + CO₂

Now calculate the theoretical yield:

49.3 g CaCO₃ × (1 mol CaCO₃ / 100 g CaCO₃) = 0.493 mol CaCO₃

0.493 mol CaCO₃ × (1 mol H₂O / 1 mol CaCO₃) = 0.493 mol H₂O

0.493 mol H₂O × (18 g H₂O / mol H₂O) = 8.87 g H₂O

Now calculate the % yield:

3.65 g H₂O / 8.87 g H₂O × 100% = 41.1%

5 0

3 years ago

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Which statement describes how the bond between two oxygen atoms is formed?

Verdich [7]

The bond that exist between two oxygen atoms is called a double covalent bond. This bond involves the sharing of four electrons to obtain a more stable structure. This type of bond is much stronger than the single covalent bond.

3 0

3 years ago

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