Identify the type or types of intermolecular forces present between molecules of the compound pictured below:
1 answer:
Answer:
dispersion, dipole-dipole, and hydrogen bonding
Explanation:
The pictured compound is an amine. Amines have high boiling points. Amines have such high boiling points because they posses about three different kinds of intermolecular interactions, viz; hydrogen bonds, dispersion forces and dipole-dipole interactions.
The dipole interactions and hydrogen bonds arise from the fact that the N-H bond is polar. Also recall that a hydrogen bond is formed when hydrogen is bonded to an electronegative element. Hydrogen bonds lead to significant intermolecular association and high boiling points.
Hence the three kinds of intermolecular forces present in the pictured compound are; hydrogen bonding, dipole interactions and dispersion forces.
You might be interested in
Explanation:
Let us assume that the ratio for the given reaction is 1:1.
Therefore, we will calculate the moles of as follows.
Moles of solution = molarity × volume (L)
= 0.0440 M × 0.014 L
= 0.000616 moles
Moles of excess EDTA = 0.000616 moles
Also, the initial moles of EDTA will be calculated as follows.
Total initial moles of EDTA = 0.0600 M × 0.025 L
= 0.0015
Therefore, moles of EDTA reacted with will be as follows.
= 0.0015 - 0.000616
= 0.00088 moles
Since, we have supposed a 1 : 1 ratio between and EDTA
.
So, moles of = 0.00088 moles
Now, we will calculate the molarity of as follows.
Molarity of solution =
=
= 0.015 M
Thus, we can conclude that the original concentration of the solution is 0.015 M.