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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics

1 answer:

Sedaia [141]3 years ago

6 0

Blu ! The formula is right THERE, IN the question. All you have to do is plug numbers into it.

The formula: Kinetic Energy = 1/2 m v²

' m ' is 2,000 kg

' v ' is 22 m/s

Now pluggum in:

KE = (1/2) (2,000 kg) (22 m/s)²

KE = (1/2) (2,000 kg) (22 m/s x 22 m/s)

KE = (1/2) (2,000 kg) (484 m²/s²)

I'm sure you can finish it off from this point, and pick the correct choice.

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What are the approximate dimensions of the smallest object on Earth that astronauts can resolve by eye when they are orbiting 27

gayaneshka [121]

Answer:

s_400 = 16.5 m , s_700 = 29.4 m

Explanation:

The limit of the human eye's solution is determined by the diffraction limit that is given by the expression

θ = 1.22 λ / D

where you lick the wavelength and D the mediator of the circular aperture.

In our case, the dilated pupil has a diameter of approximately 8 mm = 8 10-3 m and the eye responds to a wavelength between 400 nm and 700 nm.

by introducing these values into the formula

λ = 400 nm θ = 1.22 400 10⁻⁹ / 8 10⁻³ = 6 10⁻⁵ rad

λ = 700 nm θ = 1.22 700 10⁻⁹ / 8 10⁻³-3 = 1.07 10⁻⁴ rad

Now we can use the definition radians

θ= s / R

where s is the supported arc and R is the radius. Let's find the sarcos for each case

λ = 400 nm s_400 = θ R

S_400 = 6 10⁻⁵ 275 10³

s_400 = 16.5 m

λ = 700 nm s_ 700 = 1.07 10⁻⁴ 275 10³

s_700 = 29.4 m

8 0

4 years ago

A hot air balloon is filled with 1.45 × 10 6 L of an ideal gas on a cool morning ( 11 ∘ C ) . The air is heated to 109 ∘ C . Wha

just olya [345]

Answer:

The volume of air after the balloon is heated = 1.95 × 10⁶ L

Explanation:

Charles Law: Charles' law states that the volume of a given mass of gas is directly proportional to the temperature in Kelvin, provided that the pressure remains constant.

It can be expressed mathematically as,

V₁/T₁ = V₂/T₂

Making V₂ The subject of the equation

V₂ = (V₁/T₁)T₂.................... Equation 1

Where V₁ = Initial Volume, T₁ = Initial Temperature, V₂ = Final Volume, T₂ = final Temperature

Given: V₁ = 1.45 × 10⁶ L, T₁ = 11 °C = (11 + 273) K = 284 K, T₂ = 109 °C = (109 + 273) = 382 K.

Substituting these values into equation 1 above,

V₂ = (1.45×10⁶)382/284

V₂ = 1.95 × 10⁶ L

Therefore the volume of air after the balloon is heated = 1.95 × 10⁶ L

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Answer:

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Explanation:

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