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3 years ago

I need Math Geniuses!

Mathematics

1 answer:

Masja [62]3 years ago

3 0

Answer:

its c and yes I'm still here

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Help me with these2 question plz and I will press the thanks button

den301095 [7]

7) 62 - 9.817
= 52 . 183

8) 35.1 + 4.89
= 39 . 99

Hope I can help you :)

6 0

3 years ago

Which congruence theorem can be used to prove ABDA - ABDC?

oee [108]

Answer:

SAS(SIDE ANGLE SIDE)

Step-by-step explanation

AB side in ABDA = AB side in ABDC

ABD angle in ABDA= ABD angle in ABDC

BD side in ABDA = BD side in ABDC

5 0

3 years ago

Given the expression 350(1+0.05)^6, which number is a factor

solong [7]

The answer is D or
350

7 0

3 years ago

Read 2 more answers

Identify the a b and c values of the following quadratic expression 4x^2+5x=4

yarga [219]

A is the 4

B is the 5

and C is also 4.

A is always the number in front of x^2. B is always the number i front of the normal x, and C is the number that is on the other side of the equal sign!

6 0

3 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):