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Zanzabum
3 years ago
5

Find the value of Sin^-1(tan (pi/4)) a.0 b.pi c.2 d.pi/2

Mathematics
2 answers:
raketka [301]3 years ago
8 0

Answer:

D

Step-by-step explanation:

ahrayia [7]3 years ago
6 0

we are given

sin^{-1}(tan(\frac{\pi}{4}))

Let's assume entire term as x

sin^{-1}(tan(\frac{\pi}{4}))=x

now, we can take both sides as sin

sin(sin^{-1}(tan(\frac{\pi}{4})))=sin(x)

since, sin and sin^-1 are inverse of each other

so, they will get cancelled

and we get

tan(\frac{\pi}{4})=sin(x)

now, we know that

tan(pi/4)=1

1=sin(x)

and sin is 1 at pi/2

so, we get

x=\frac{\pi}{2}

so, option-D.........Answer

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you put $400 in an account. the account earns $18 simple interest in 3 years. what is the annual interest​
nadya68 [22]

Answer:

$6

Step-by-step explanation:

divide 18 into three

18÷3=6

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Step-by-step explanation:

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Solve the following using Substitution method<br> 2x – 5y = -13<br><br> 3x + 4y = 15
Digiron [165]

\huge \boxed{\mathfrak{Question} \downarrow}

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\left. \begin{array}  { l  }  { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.

  • To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

2x-5y=-13, \: 3x+4y=15

  • Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

2x-5y=-13

  • Add 5y to both sides of the equation.

2x=5y-13

  • Divide both sides by 2.

x=\frac{1}{2}\left(5y-13\right)  \\

  • Multiply \frac{1}{2}\\ times 5y - 13.

x=\frac{5}{2}y-\frac{13}{2}  \\

  • Substitute \frac{5y-13}{2}\\ for x in the other equation, 3x + 4y = 15.

3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15  \\

  • Multiply 3 times \frac{5y-13}{2}\\.

\frac{15}{2}y-\frac{39}{2}+4y=15  \\

  • Add \frac{15y}{2} \\ to 4y.

\frac{23}{2}y-\frac{39}{2}=15  \\

  • Add \frac{39}{2}\\ to both sides of the equation.

\frac{23}{2}y=\frac{69}{2}  \\

  • Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

\large \underline{ \underline{ \sf \: y=3 }}

  • Substitute 3 for y in x=\frac{5}{2}y-\frac{13}{2}\\. Because the resulting equation contains only one variable, you can solve for x directly.

x=\frac{5}{2}\times 3-\frac{13}{2}  \\

  • Multiply 5/2 times 3.

x=\frac{15-13}{2}  \\

  • Add -\frac{13}{2}\\ to \frac{15}{2}\\ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

\large\underline{ \underline{ \sf \: x=1 }}

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\huge\boxed{  \boxed{\bf \: x=1, \: y=3 }}

8 0
2 years ago
What is z? -0.25z = -1.25
lora16 [44]
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3 0
3 years ago
Read 2 more answers
A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. Th
Olegator [25]

Answer:

(a) 74553

(b) 172120

(c) 234802

Step-by-step explanation:

Given

y = \frac{340110}{1 + 377e^{-0.259t}}

Solving (a): 1998

Year 1998 means that:

t =1998 -  1980

t =18

So, we have:

y = \frac{340110}{1 + 377e^{-0.259*18}}

y = \frac{340110}{1 + 377e^{-4.662}}

y = \frac{340110}{1 + 3.562}

y = \frac{340110}{4.562}

y = 74553 --- approximated

Solving (b): 2003

Year 2003 means that:

t = 2003 -  1980

t =23

So, we have:

y = \frac{340110}{1 + 377e^{-0.259*23}}

y = \frac{340110}{1 + 377e^{-5.957}}

y = \frac{340110}{1 + 0.976}

y = \frac{340110}{1.976}

y = 172120 --- approximated

Solving (c): 2006

Year 2006 means that:

t = 2006 -  1980

t =26

So, we have:

y = \frac{340110}{1 + 377e^{-0.259*26}}

y = \frac{340110}{1 + 377e^{-6.734}}

y = \frac{340110}{1 + 0.4485}

y = \frac{340110}{1.4485}

y = 234802 --- approximated

3 0
2 years ago
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