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KiRa [710]
3 years ago
7

Find X A. 3 B. sqrt6 C. 3sqrt3 D. 3sqrt2/2

Mathematics
1 answer:
Jet001 [13]3 years ago
5 0

Answer:

B. sqrt 6 is the answer.maja

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Aye someone please help ?
monitta

Answer:

The required rectangular form of the given complex polar form :

z1 = -3√2 - 3√2i

Step-by-step explanation:

z_1=6[\cos (\frac{5\pi}{4}) + i\sin(\frac{5\pi}{4})]...........(1)\\\\Now,\cos (\frac{5\pi}{4})=\cos(\pi+\frac{\pi}{4})\\\\=-\cos(\frac{\pi}{4})\\\\=-\frac{1}{\sqrt{2}}\\\\And,\sin (\frac{5\pi}{4})=\sin(\pi+\frac{\pi}{4})\\\\=-\sin(\frac{\pi}{4})\\\\=-\frac{1}{\sqrt{2}}

On substituting the obtained values in equation (1)

z_1=6[\frac{-1}{\sqrt{2}}-i\cdot \frac{1}{\sqrt{2}}]\\\\\implies z_1=-3\sqrt{2}- 3\sqrt{2}\cdot i

Hence, the required rectangular form of the given complex polar form :

z1 = -3√2 - 3√2i

7 0
4 years ago
Find SP where MP=Rs875 and discount =Rs75
liraira [26]

Answer:

SP is Rs 800.

Step-by-step explanation:

MP = Rs 875

Discount = Rs 75

so

SP = MP - discount

= Rs 875 - Rs 75

= Rs 800

4 0
3 years ago
−2(x+1/4)+1=5 PLEASE HELP
PilotLPTM [1.2K]

Answer: x=−9/4

Step-by-step explanation:

Let's solve your equation step-by-step.

−2(x+14)+1=5

Step 1: Simplify both sides of the equation.

−2(x+14)+1=5(−2)(x)+(−2)(14)+1=5(Distribute)−2x+

−1

2

+1=5

(−2x)+(

−1

2

+1)=5(Combine Like Terms)

−2x+

1

2

=5

−2x+

1

2

=5

Step 2: Subtract 1/2 from both sides.

−2x+

1

2

−

1

2

=5−

1

2

−2x=

9

2

Step 3: Divide both sides by -2.

−2x

−2

=

9

2

−2

x=

−9

4

7 0
3 years ago
Read 2 more answers
1-234 +0.1-(-1.35)<br> What is the value
vesna_86 [32]

Answer:

-231.55

Step-by-step explanation:

4 0
4 years ago
Which of the following options is a Pythagorean Identity
alexdok [17]

None of them really, but C is equivalent to the Triognometric Pythagorean Theorem:


(\sin x + \cos x)^2 = 1 + 2 \sin x \cos x


\sin^2 x + 2 \sin x \cos x + \cos ^2 x = 1 + 2 \sin x \cos x


\sin^2x + \cos ^2x = 1


That's the Trigonometric Pythagorean Theorem


Answer: C



3 0
3 years ago
Read 2 more answers
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