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Dima020 [189]
3 years ago
10

If I had seven stones and I threw 8 how many stones do I have left??

Mathematics
2 answers:
igomit [66]3 years ago
7 0
It is impossible as 8 is bigger than 7 and you can’t take it away ur welcome
Mashcka [7]3 years ago
6 0
Perhaps you were madusa, and you had a friend or sum wit chu, you be like “HISSS” “YOU STONE NOW GIRLL” then you got the 8 stones ya feel, but if you threw them all, you’d have 0 left unless you found them
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Answer:

\left(x^3+2x^2-3x-1\right)+\left(4-x-x^3\right)=2x^2-4x+3

Step-by-step explanation:

To write any polynomial in standard form, you look at the degree of each term. You then write each term in order of degree, from highest to lowest, left to write.

To add the polynomials you need to:

Remove parentheses

\left(x^3+2x^2-3x-1\right)+\left(4-x-x^3\right)=x^3+2x^2-3x-1+4-x-x^3

Group like terms

\left(x^3+2x^2-3x-1\right)+\left(4-x-x^3\right)=x^3-x^3+2x^2-3x-x-1+4

Add similar elements

\left(x^3+2x^2-3x-1\right)+\left(4-x-x^3\right)=2x^2-3x-x-1+4\\\left(x^3+2x^2-3x-1\right)+\left(4-x-x^3\right)=2x^2-4x-1+4\\\left(x^3+2x^2-3x-1\right)+\left(4-x-x^3\right)=2x^2-4x+3

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