A scientist has 100 milligrams of a radioactive element. The amount of radioactive element remaining after t days can be determi
ned using the equation f(t)=100(1/2)^t/10. After three days, the scientist receives a second shipment of 100 milligrams of the same element. The equation used to represent the amount of shipment 2 remaining after t days is 100(1/2)^t-3/10. After any time, t, the mass of the element remaining in shipment 1 is what percentage of the mass of the element remaining in shipment 2?
1 answer:
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Answer:
your answer is 117
Step-by-step explanation:
2460÷12=117
i hope this helps
have a nice day/night
mark brainliest please :)
X-1=-2x+5
X=2
Y=-2(2) + 5
Y= 1
Answer:
x= 5/4 + −1/4√17 or x = 5/4 + 1/4√17
Step-by-step explanation:
548 is the correct answer.
feel free to ask any questions !!
hope this helps :)
Multiplying polynomial:
a^m * a^n = a^m + n
Hope this helped!!!
