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Whitepunk [10]
4 years ago
15

Factorize p^2+pq-pqr​

Mathematics
2 answers:
Flura [38]4 years ago
6 0

Answer:

p(p+q-qr)

Step-by-step explanation:

p^2 +pq-pqr

= p(p+q-qr)

Natasha_Volkova [10]4 years ago
4 0

Answer:

p(p+q-qr)

Step-by-step explanation:

p^2+pq-pqr​

Factor out a p

p(p+q-qr)

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Below is the table of values of a function. Write the output when the input is n .
stiv31 [10]

9514 1404 393

Answer:

  4n

Step-by-step explanation:

We observe that each output is 4 times the corresponding input. Then 4 times n will be ...

  Input: n

  Output: 4n

3 0
4 years ago
Which polynomial function has a leading coefficient of 1 and roots (7 i) and (5 – i) with multiplicity 1? f(x) = (x 7)(x – i)(x
Nuetrik [128]

It looks like you might have intended to say the roots are 7 + i and 5 - i, judging by the extra space between 7 and i.

The simplest polynomial with these characteristics would be

f(x) = (x - (7 + i)) (x - (5 - i))

but seeing as each of the options appears to be a quartic polynomial, I suspect f(x) is also supposed to have only real coefficients. In that case, we need to pair up any complex root with its conjugate to "complete" f(x). We end up with

f(x) = (x - (7 + i)) (x - (7 - i)) (x - (5 - i)) (x - (5 + i))

which appears to most closely resemble the third option. Upon expanding, we see f(x) does indeed have real coefficients:

f(x) = (x^2 - (7^2 - i^2)) (x^2 - (5^2 - i^2)) = (x^2 - 8) (x^2 - 6) = x^4 - 14x^2 + 48

5 0
2 years ago
Add 4x²y,-2xy²,-5xy²,3x²y plz explain​
Vinil7 [7]
4x^2 - 2xy^2
5xy^2 +
3x^2y
_____________
12x^5y^4-2xy^2

This is so because 4+5+3 is 12, then using laws of indices to add your x and y you get x^5 and y^4

To simplify your answer to the lowest you have it in the form of
3x^2y^2(4x^2y - 2xy^2)

If you multiply this as well you get the same answer I got with the addition
3 0
3 years ago
Triangle ABC is shown below.
zhannawk [14.2K]

Answer:

b

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
Which equation is perpendicular to the y axis
docker41 [41]
C is the only one that is perpendicular.
The quickest way I can explain it is that the y-axis runs up and down, making the slope undefined. Something perpendicular to an undefined slope is a 0-slope. The only equation of the choices that has a 0-slope is C. Comment if you want a more detailed answer.
6 0
3 years ago
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