Answer: 12 yearly admissions and 38 single admissions
Step-by-step explanation:
Let x be yearly membership
Let y be single admission
x+y=50 --> # of tickets sold
35.25x+6.25y=660.50 --> $ of tickets
Use elimination method to solve (multiply equation 1 by -3525 and equation 2 by 100)
-3525x-3525y=-176250
+ 3525+625y=66050
-----------------------------------
-2900y=-110200
y=38
Substitute y=38 into equation 1
x+38=50
x=12
Therefore, 12 yearly admissions and 38 single admissions were sold
-2 or 2 either one
Hope this helps
Answer:
Lonnie is not correct
Step-by-step explanation:
Answer:
Joe: 3 hrs
Janet: 6hrs
Step-by-step explanation:
joe takes x hours
so in 1 hr he does 1/x of the garden
janet takes 2x hours
so in 1 hr she does 1/(2x) of the garden
In one hour together they do 1/2 of the garden
1/x + 1/(2x) = 1/2
2/(2x) + 1/(2x) = 1/2
3/(2x) = 1/2
Cross multiply
6 = 2x
x = 3
Joe: 3 hrs
Janet: 6hrs
7/12 times 4 is 2 1/3. So 2 1/3 inches each week
